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barxatty [35]
3 years ago
13

Suppose you are presented with a clear solution of sodium thiosulfate, Na2S2O3 . How could you determine whether the solution is

unsaturated, saturated, or supersaturated?
Chemistry
1 answer:
navik [9.2K]3 years ago
5 0

Explanation:

A solution is said to saturated when it cannot dissolve any extra solute in it. The extra solute put remains undissolved.

A solution is said to unsaturated, when the concentration of solute is less as compared to solubility of the solution it is said to be unsaturated.

A solution is said to be super saturated when it contains more of the solute than the solvent  can dissolve under normal conditions is called super saturated.

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Taya2010 [7]

Explanation:

Moles of metal,

=

4.86

⋅

g

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⋅

g

⋅

m

o

l

−

1

=

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m

o

l

.

Moles of

H

C

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=

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⋅

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−

3

×

2.00

⋅

m

o

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⋅

d

m

−

3

=

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m

o

l

Clearly, the acid is in deficiency ; i.e. it is the limiting reagent, because the equation above specifies that that 2 equiv of HCl are required for each equiv of metal.

So if

0.200

m

o

l

acid react, then (by the stoichiometry), 1/2 this quantity, i.e.

0.100

m

o

l

of dihydrogen will evolve.

So,

0.100

m

o

l

dihydrogen are evolved; this has a mass of

0.100

⋅

m

o

l

×

2.00

⋅

g

⋅

m

o

l

−

1

=

?

?

g

.

If 1 mol dihydrogen gas occupies

24.5

d

m

3

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