Answer:
Explanation:
<u>1) Data:</u>
<em />
a) V = 75.0 liter
b) n = 15.82 mol
c) p = 546.8 kPa
d) T = ?
<u>2) Formula:</u>
- Ideal gas equation: pV = nRT
Where:
- n = number of moles
- V = volume
- p = absolute pressure
- T = absolute temperature
- R = Universal Gas constat: 8.314 kPa - liter / K-mol
<u>3) Solution:</u>
a) <u>Solve the equation for T</u>:
b) <u>Substitute and compute</u>:
- T = 546.8 kPa × 75.0 l iter / (15.82 mol × 8.314 kPa-liter/K-mol) = 312 K
(since the volume is expressed with 3 significant figures, the answer must show also 3 significant figures)
Answer:
For this angular momentum, no quantum number exist
Explanation:
From the question we are told that
The magnitude of the angular momentum is 
The generally formula for Orbital angular momentum is mathematically represented as
Where 
is the quantum number
now
We can look at the given angular momentum in this form as
comparing this equation to the generally equation for Orbital angular momentum
We see that there is no quantum number that would satisfy this equation
It would mean that they have the same oxidation number.
Is there a question that needs to be answered
Answer:
Distribution coefficient: 4.79
Explanation:
Distribution coefficient is the ratio between equilibrium concentration of non-aqueous phase and aqueous phase where both solvents are inmiscible. The equation for the problem is:
Distribution coefficient: Concentration in chloroform / Concentration in Water
<em>Concentration in water: 2.59mg / 30mL = 0.08633mg/mL</em>
<em>Concentration in chloroform: (15mg-2.59mg) / 30mL = 0.4137mg/mL</em>
<em />
Distribution coefficient: 0.4137mg/mL / 0.08633mg/mL
<h3>Distribution coefficient: 4.79</h3>
