1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
egoroff_w [7]
3 years ago
6

In the javelin throw at a track-and-field event, the javelin is launched at a speed of 29 m/s at an angle of 36???? above the ho

rizontal. As the javelin travels upward, its velocity points above the horizontal at an angle that decreases as time passes. How much time is required for the angle to be reduced from 36???? at launch to 18?????
Physics
1 answer:
netineya [11]3 years ago
6 0

Answer:

t = 0.96 s  is the time it takes for the angle to reduce

Explanation:

In the launch of projectiles, the velocity is broken down into its x and y components, the velocity in the x-axis is constant, as there is no acceleration, instead the velocity in the axis and is reduced by the effect of the acceleration of gravity.

We can find Vox for the initial conditions

  Voy  = Vo sin θ

  Voy = 29 sin 36

  VoY = 17 m/s

  Vox = Vo cos θ

  Vox = 29 cos 36

  Vox= 23.5 m/s

  Vx = Vox  

The velocity on the x axis is constant

By trigonometry, we find the firing angle

 

  tan θ = Voy/ Vx

  Vy = Vx tan θ

  Vy = 23.5 tan 18

  Vy = 7.64 m/s

Now that we have the vertical speed we can find the time

   Vy = I'm going - g t

   t = (Vy -Voy) / g

   t = (17 - 7.64) /9.8

   t = 0.96 s

Be the time it takes for the angle to reduce

You might be interested in
The Federal Communications Commission (FCC) has considered lifting the ban on in-flight cell phone use. This could allow people
olga nikolaevna [1]
I would say that there shouldn't be any calls on a plane while in-flight because you never know what someone is calling for. It can lead to a bad situation like 9/11 or any form of terrorism. 
7 0
4 years ago
Read 2 more answers
A girl swings on a playground swing in such a way that at her highest point she is 4.1 m from the ground, while at her lowest po
Umnica [9.8K]

Answer:

V1 =8.1 m/s

Explanation:

height at highest point (h2) = 4.1 m

height at lowest point (h1) = 0.8 m

acceleration due to gravity (g) = 9.8 m/s^{2}

from conservation of energy, the total energy at the lowest point will be the same as the total energy at the highest point. therefore

mgh1 + 0.5mV1^{2} = mgh2 + 0.5mV2^{2}

where

  • speed at highest point = V2
  • speed at lowest point = V1
  • mass of the girl and swing = m
  • at the highest point, the  speed is minimum (V1 = 0)
  • at the lowest point the speed is maximum (V2 is the maximum speed)
  • therefore the equation becomes mgh1 + 0.5mV1^{2} = mgh2

      m(gh1 + 0.5V1^{2}) = m(gh2)

      gh1 + 0.5V1^{2} = gh2

      V1 = \sqrt{\frac{gh2 - gh1}{0.5}}

now we can substitute all required values into the equation above.

V1 = \sqrt{\frac{(9.8x4.1) - (9.8x0.8)}{0.5}}

V1 = \sqrt{\frac{32.34}{0.5}}

V1 =8.1 m/s

8 0
4 years ago
From the ground an object is vertically thrown upwards with an angle of theta.
Mashutka [201]

Answer:

u/2 √(1 + 3 cos² θ)

Explanation:

The object is thrown at an angle θ, so the velocity has two components, vertical and horizontal.

Initially, the vertical component is u sin θ and the horizontal component is u cos θ.

At the maximum height, the vertical component is 0 and the horizontal component is u cos θ.

The mean vertical velocity is:

(u sin θ + 0) / 2 = u/2 sin θ

The mean horizontal velocity is:

(u cos θ + u cos θ) / 2 = u cos θ

The net mean velocity can be found with Pythagorean theorem:

v² = (u/2 sin θ)² + (u cos θ)²

v² = u²/4 sin² θ + u² cos² θ

v² = u²/4 (1 − cos² θ) + u² cos² θ

v² = u²/4 (1 − cos² θ) + u²/4 (4 cos² θ)

v² = u²/4 (1 − cos² θ + 4 cos² θ)

v² = u²/4 (1 + 3 cos² θ)

v = u/2 √(1 + 3 cos² θ)

8 0
4 years ago
What is the general pattern of the planetary distances from the sun
eimsori [14]

Answer:

The Titius–Bode law (sometimes termed just Bode's law) is a hypothesis that the bodies in some orbital systems, including the Sun's, orbit at semi-major axes in a function of planetary sequence. The formula suggests that, extending outward, each planet would be approximately twice as far from the Sun as the one before.

Explanation:

8 0
4 years ago
The rotating drum in a clothes-dryer has a radius of 0.31 m. If the acceleration at the rim of the drum is 27 m/s2, what is the
olga nikolaevna [1]

Answer:

v = 2.89 m / s

Explanation:

This is a kinematics exercise, the centripetal acceleration is

         a = v² / r

where a is the acceleration, v is the velocity and r the radius

let's clear

       v = √a r

let's calculate

       v = √ (27 0.31)

       

       v = 2.89 m / s

this is the speed of the drum which is constant

3 0
3 years ago
Other questions:
  • Calculate the density of the following material: 500 kg gold with a volume of 0.026 m³
    10·2 answers
  • What are three good things plate tectonics provide for humans?
    12·1 answer
  • 3. A sled is initially given a shove up a frictionless 23.0° incline. It reaches a maximum vertical height 1.22 m higher than wh
    14·1 answer
  • Determine the minimum amount of energy needed to move a satellite from its orbit around the Earth to an infinite distance from t
    5·1 answer
  • What is the exact meaning of croos section and cross sectional area of a conductor?
    13·1 answer
  • 14) the formula k2s indicates that
    15·1 answer
  • First to answer will be the brainliest
    5·1 answer
  • Practice
    8·1 answer
  • According to Newton's third law of motion, if you push against a wall, the wall will __________.
    15·2 answers
  • How much is done when moving a box 25 m with a net force of 30 N?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!