Answer:
0.625 g/m
Explanation:
The fundamental frequency of a tensioned string is:
f = √(T/ρ) / (2L)
where T is the tension,
ρ is the mass per length linear density,
and L is the length of the string.
Solving for ρ:
2Lf = √(T/ρ)
4(Lf)² = T/ρ
ρ = T / (4(Lf)²)
Given T = 100 N, L = 2 m, and f = 100 Hz:
ρ = 100 / (4 (2×100)²)
ρ = 100 / (4 × 40000)
ρ = 1/1600
ρ = 0.000625 kg/m
ρ = 0.625 g/m
Answer:
0.000311 m³
Explanation:
The formula that connect volume, mass and density is given below
D = m/v ...................... Equation 1
Where D = Density of the gold, m = mass of the gold, v = volume of the gold.
make v the subject of the equation
v = m/D .................. Equation 2
Given: m = 6 kg,
Note the density of pure gold = 19300 kg/m².
Substitute into equation 2
v = 6/19300
v = 0.000311 m³
Hence the volume that will verify that it's a pure gold = 0.000311 m³
Answer:19.32 m/s
Explanation:
Given
initial speed of car(u)=4.92 m/s
acceleration(a)=
Speed of car after 4.5 s
using equation of motion
v=u+at
v=19.32 m/s
Displacement of the car after 4.5 s
s=54.54 m
Answer:
Yes Newton's laws apply to small objects
EX: Newton s first law
when body at rest always want to be at rest
or body at motion always want to be at motion
unles an external force acts upon it
for example a eraser on the table will be at rest
if so e apply some force then it comes motion
so, Newton s law apply to small object s