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3 years ago

58% of what number is 29

Mathematics

1 answer:

Mandarinka [93]3 years ago

6 0

Method 1:

$p\%=\dfrac{p}{100}\\\\58\%=\dfrac{58}{100}=0.58\\\\n-a\ number\\\\0.58n=29\ \ \ \ |:0.58\\\\\boxed{n=50}$

Method 2:

$\begin{array}{ccc}58\%&-&29\\100\%&-&n\end{array}\ \ \ \ \text{cross multiply}\\\\58n=2900\ \ \ \ |:58\\\\\boxed{n=50}$

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Leno4ka [110]

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4 years ago

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JulsSmile [24]

Answer:

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Step-by-step explanation:

In this problem we have:

$d_1=1 mi$ is the distance travelled during the 1st day

$d_2=1.3 mi$ is the distance travelled during the 2nd day

$d_3=1.9 mi$ is the distance travelled during the 3rd day

$d_4=3.1 mi$ is the distance travelled during the 4th day

We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:

$d_2-d_1=0.3\\d_3-d_2=2\cdot 0.3 = 0.6\\d_4-d_3=2\cdot 0.6 = 1.2$

Which can be rewritten using the general formula:

$d_{n+1}-d_n=2(d_n-d_{n-1})$

This means that

$d_{n+1}=d_n+2(d_n-d_{n-1})$

By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

$d_1=1\\d_2=1.3\\d_3=1.9\\d_4=3.1\\d_5=3.1+2\cdot 1.2=5.5\\d_6=5.5+2\cdot 2.4=10.3\\d_7=10.3+2\cdot 4.8=19.9 mi$

So, the distance travelled on the 7th day is 19.9 miles.

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4 years ago

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The answer to your question is 15

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4 years ago

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lubasha [3.4K]

Answer:

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3 years ago