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miv72 [106K]
3 years ago
15

You’re speeding at 85 km/hr when you notice that you’re only 10 m behind the car in front of you,

Physics
1 answer:
solmaris [256]3 years ago
7 0
Your position in meters will, measured relative to the starting point of the car behind you, be 
x1(t) = 10 + 23.61 t - 1/2 4.2 t^2 
his position will be 
x2(t) = 16.67 t 
Hence at any time the separation s(t) will be 
s(t) = x1(t) - x2(t) = 10 + 6.94 t -2.1 t^2 
Now I assume you mean that you will decelerate UNTIl you are driving at the legal speed limit (60 km/h). That will take you: 
16.67 m/s = 23.61m/s - 4.2 m/s^2 * t 
t = 1.65 seconds 
What is the separation at that time? If it is still greater than zero, there will be no collision: 
s(1.65) = 10 + 6.94 *1.65 -2.1 (1.65)^2 = 15.73 meters. 
Hence you will NOT collide. The 1.65 s you calculated was the time needed to brake to the speed of 60 km/h. 
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Answer:

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Explanation:

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The friction force between both cubes (F) is defined as the normal force acting on the smaller cube multiplied by the coefficient of static friction. Since both cubes are subject to the same acceleration:

F = m * a*\mu \\F= 4.3*0.710*\frac{P}{32.9}\\F=3.053*\frac{P}{32.9}

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3.053*\frac{P}{32.9} = 4.3 * g\\\\P = \frac{4.3*9.8*32.9}{3.053} \\P= 454.11 N

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