Question

if 6.02 x 10 23 molecules of N2 react according to the equation N2 +3h2 2NH3, the total number of molecules of NH3 is produced is ?

Answer 1

N2+3H2---->2NH3
6.02×10 23 equals to one mole. if one mole of N2 enters reaction 2NH3 isproduced , so 2×6.02 10 23
12.04 × 10 23

Answer 2

Answer:

$Molec_{NH3}=1.204x10^{24}molec_{NH_3}$

Explanation:

Hello,

In this case, we apply a set of proportional factors to provide the total number of molecules of ammonia that are produced, taking into account the 1 to 2 relationship between nitrogen and ammonia (based on the undergoing chemical reaction) and the fact that one mole of substance is related with the Avogadro's number in terms of molecules in this case, in such a way, we apply the shown below procedure:

$Molec_{NH3}=6.02x10^{23}molec_{N_2}*\frac{1molN_2}{6.022x10^{23}molec_{N_2}}*\frac{2molNH_3}{1molN_2}*\frac{6.022x10^{23}molec_{NH_3}}{1molNH_3} \\Molec_{NH3}=1.204x10^{24}molec_{NH_3}$

Best regards.