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Galina-37 [17]
3 years ago
7

J. J. Thomson’s experiment disproved the theory that an atom

Chemistry
2 answers:
gizmo_the_mogwai [7]3 years ago
7 0

Answer : J. J. Thomson’s experiment disproved the theory that an atom is indivisible.

Explanation : Scientist J.J. Thomson did his experiment to prove the existence of electrons. He did the experiment using a cathode ray tube, in which a vacuum-sealed tube with a cathode and anode on one end was placed which created a beam of electrons that traveled towards the other end of the tube. This was the theory that proved that atoms consists of many subatomic particles namely electrons.

Finger [1]3 years ago
7 0
The choices can be found elsewhere and as follows:

<span>is divisible.
is indivisible.
contains protons.
contains electrons.

I believe the correct answer is the second option. </span><span>J. J. Thomson’s experiment disproved the theory that an atom is indivisible. Hope this answers the question.</span>
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Read 2 more answers
A 0.708 g sample of a metal, M, reacts completely with sulfuric acid according to the reaction M ( s ) + H 2 SO 4 ( aq ) ⟶ MSO 4
ollegr [7]

Answer:

The metal has a molar mass of 65.37 g/mol

Explanation:

Step 1: Data given

Mass of the metal = 0.708 grams

Volume of hydrogen = 275 mL = 0.275 L

Atmospheric pressure = 1.0079 bar = 0.9947 atm

Temperature = 25°C

Vapor pressure of water at 25 °C = 0.03167 bar = 0.03126 atm

Step 2: The balanced equation

M(s) + H2SO4(aq) ⟶ MSO4 (aq) + H2(g)

Step 3: Calculate pH2

Atmospheric pressure = vapor pressure of water + pressure of H2

0.9947 atm = 0.03126 atm + pressure of H2

Pressure of H2 = 0.9947 - 0.03126

Pressure of H2 = 0.96344 atm

Step 4: Calculate moles of H2

p*V=n*R*T

⇒ with p = The pressure of H2 = 0.96344 atm

⇒ with V = the volume of H2 = 0.275 L

⇒ with n = the number of moles H2 = TO BE DETERMINED

⇒ with R = the gas constant = 0.08206 L*atm/K*mol

⇒ with T = the temperature = 25°C = 298 Kelvin

n = (p*V)/(R*T)

n = (0.96344 * 0.275)/(0.08206*298)

n = 0.01083 moles

Step 5: Calculate moles of M

For 1 mole of H2 produced, we need 1 mole M

For 0.0108 moles of H2 we need 0.01083 moles of M

Step 6: Calculate molar mass of M

Molar mass M = Mass M / moles M

Molar mass M = 0.708 grams / 0.01083 moles

Molar mass M = 65.37 g/mol

The metal has a molar mass of 65.37 g/mol

5 0
3 years ago
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