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Stels [109]
3 years ago
6

Which statement best describes a device that has a high energy efficiency? Its ratio of energy absorbed to energy released is hi

gh. Its ratio of energy input to energy output is high. It wastes little energy. It wastes a lot of energy.
Physics
2 answers:
Serggg [28]3 years ago
5 0

Answer: The answer is that it wastes little energy.

Stels [109]3 years ago
3 0

Answer:

It wastes little energy

Explanation:

  • The efficiency of a machine refers to the ratio of work output to the work input as a percentage.
  • The efficiency of most machines is less than 100% because some work is lost  due to friction and heat.
  • Therefore, a machine with high efficiency has less wastage of energy due to factors such as friction of the moving parts. Conversely, low efficiency means there is more wastage of energy.
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An elevator lifts a total mass of 1.1×103 kg a distance of 40.0 m in 12.5 s. How much power does the elevator deliver?
Harman [31]

The power delivered by the elevator is 34496 W.

<h3>What is power?</h3>

Power is the rate at which energy is used up.

To calculate the power delivered by the elevator, we use the formula below.

Formula:

  • P = mgh/t.............. Equation 1

Where:

  • P = Power delivered by the elevator
  • m = Total mass on the elevator
  • g = acceleration due to gravity
  • h = Height

From the question,

Given:

  • m = 1.1×10³ kg
  • h = 40 m
  • t = 12.5 s
  • g = 9.8 m/s²

Substitute these values into equation 1

  • P = 1.1×10³×40×9.8/12.5
  • P = 34496 W.

Hence, the power delivered by the elevator is 34496 W.

Learn more about power here: brainly.com/question/24858512

#SPJ1

8 0
2 years ago
Justin is riding his bike up Dunmore Hill. The effort force from his feet on his pedals is 1160N.
Schach [20]

Explanation:

the answer is 1835N that how best I can help

3 0
3 years ago
Very far from earth (at R- oo), a spacecraft has run out of fuel and its kinetic energy is zero. If only the gravitational force
Margaret [11]

Answer:

Speed of the spacecraft right before the collision: \displaystyle \sqrt{\frac{2\, G\cdot M_\text{e}}{R\text{e}}}.

Assumption: the earth is exactly spherical with a uniform density.

Explanation:

This question could be solved using the conservation of energy.

The mechanical energy of this spacecraft is the sum of:

  • the kinetic energy of this spacecraft, and
  • the (gravitational) potential energy of this spacecraft.

Let m denote the mass of this spacecraft. At a distance of R from the center of the earth (with mass M_\text{e}), the gravitational potential energy (\mathrm{GPE}) of this spacecraft would be:

\displaystyle \text{GPE} = -\frac{G \cdot M_\text{e}\cdot m}{R}.

Initially, R (the denominator of this fraction) is infinitely large. Therefore, the initial value of \mathrm{GPE} will be infinitely close to zero.

On the other hand, the question states that the initial kinetic energy (\rm KE) of this spacecraft is also zero. Therefore, the initial mechanical energy of this spacecraft would be zero.

Right before the collision, the spacecraft would be very close to the surface of the earth. The distance R between the spacecraft and the center of the earth would be approximately equal to R_\text{e}, the radius of the earth.

The \mathrm{GPE} of the spacecraft at that moment would be:

\displaystyle \text{GPE} = -\frac{G \cdot M_\text{e}\cdot m}{R_\text{e}}.

Subtract this value from zero to find the loss in the \rm GPE of this spacecraft:

\begin{aligned}\text{GPE change} &= \text{Initial GPE} - \text{Final GPE} \\ &= 0 - \left(-\frac{G \cdot M_\text{e}\cdot m}{R_\text{e}}\right) = \frac{G \cdot M_\text{e}\cdot m}{R_\text{e}} \end{aligned}

Assume that gravitational pull is the only force on the spacecraft. The size of the loss in the \rm GPE of this spacecraft would be equal to the size of the gain in its \rm KE.

Therefore, right before collision, the \rm KE of this spacecraft would be:

\begin{aligned}& \text{Initial KE} + \text{KE change} \\ &= \text{Initial KE} + (-\text{GPE change}) \\ &= 0 + \frac{G \cdot M_\text{e}\cdot m}{R_\text{e}} \\ &= \frac{G \cdot M_\text{e}\cdot m}{R_\text{e}}\end{aligned}.

On the other hand, let v denote the speed of this spacecraft. The following equation that relates v\! and m to \rm KE:

\displaystyle \text{KE} = \frac{1}{2}\, m \cdot v^2.

Rearrange this equation to find an equation for v:

\displaystyle v = \sqrt{\frac{2\, \text{KE}}{m}}.

It is already found that right before the collision, \displaystyle \text{KE} = \frac{G \cdot M_\text{e}\cdot m}{R_\text{e}}. Make use of this equation to find v at that moment:

\begin{aligned}v &= \sqrt{\frac{2\, \text{KE}}{m}} \\ &= \sqrt{\frac{2\, G\cdot M_\text{e} \cdot m}{R_\text{e}\cdot m}} = \sqrt{\frac{2\, G\cdot M_\text{e}}{R_\text{e}}}\end{aligned}.

6 0
3 years ago
When a wave moves from one medium to another, which properties of the wave change? choose all that apply.
Furkat [3]

In most cases, when wave refract, frequency and amplitude will be constant while wavelength and speed will change.

<h3>PROPERTIES OF WAVES</h3>

The four properties of waves are:

  • Frequency
  • Amplitude
  • Wavelength
  • Speed

When a wave moves from one medium to another, the wave will undergo refraction.

When a wave move for instance, from water to glass, the wave will refract by changing direction. In most scenario, the frequency of the wave will be constant while the wavelength of the wave will change. Since the wavelength will change, the speed will also change.

Therefore, when a wave moves from one medium to another, the properties of the wave that change are wavelength and wave speed.

Learn more about Wave here: brainly.com/question/12215474

8 0
2 years ago
Ned is learning about cells in science class. He drew a picture to model a cell. What can he show with his cell drawing?
ICE Princess25 [194]

Answer:I need the answer pls

Explanation:

I don't have one

3 0
3 years ago
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