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FinnZ [79.3K]
3 years ago
14

Please use the values in the resources listed below instead of the textbook values. Under certain conditions the decomposition o

f ammonia on a metal surface gives the following data.[NH3] (M) 2.0 ✕ 10−3 4.0 ✕ 10−3 6.0 ✕ 10−3 Rate (mol/L/h) 1.5 ✕ 10−6 1.5 ✕ 10−6 1.5 ✕ 10−6 Determine the rate equation for this reaction. (Rate expressions take the general form: rate = k . [A]a . [B]b.)
Chemistry
1 answer:
Alex787 [66]3 years ago
4 0

Answer:

The rate equation for this reaction:

R=k[NH_3]^0

Explanation:

Decomposition of ammonia:

2NH_3\rightarrow N_2+3H_2

Rate law of the can be written as;

R=k[NH_3]^x

1) Rate of the reaction , when [NH_3]=2.0\times 10^{-3} M

1.5\times 10^{-6} M/s=k[2.0\times 10^{-3} M]^x..[1]

2) Rate of the reaction , when [NH_3]=4.0\times 10^{-3} M

1.5\times 10^{-6} M/s=k[4.0\times 10^{-3} M]^x..[2]

[1] ÷ [2]

\frac{1.5\times 10^{-6}M/s}{1.5\times 10^{-6}M/s}=\frac{k[2.0\times 10^{-3}M]^x}{k[4.0\times 10^{-3}M]^x}

On solving for x , we get ;

x = 0

The rate equation for this reaction:

R=k[NH_3]^0

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According to the VSEPR hypothesis, each atom in a molecule will develop a shape that reduces the repulsion between its valence shell electrons.

<h3>What is the basis of VSEPR theory?</h3>

According to the valence-shell electron pair repulsion model, or VSEPR model, a molecule will modify its structure to maintain the greatest feasible distance between the valence electron pairs (based on the repulsive behavior of electron pairs). Given that negatively charged electrons repel one another, this makes sense.

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Electron pairings resemble groups of individuals who don't get along. They "like" to keep a safe distance between one another. Because carbon has only two electron domains, the molecular geometry of carbon dioxide is linear.

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Sulfur tetrafluoride is a trigonal bipyramidal molecule with four bonded and one non-bonding electron pair, or domain. The "shared" region between the two atoms is where the electrons in a covalent bond are most likely to be located. They become high electron density, compact zones as a result.

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Answer:

\boxed {\boxed {\sf 0.4 \ mol \ HCl}}

Explanation:

Molarity is concentration measured in moles per liters. It is the number of moles of solute per liters of solution. The formula is:

molarity= \frac{moles \ of \ solute}{liters \ of \ solution}}

We know the solution of HCl has a molarity of 0.5 molar and there are 0.8 liters of solution.

  • 1 molar (M) is equal to 1 mole per liter.
  • Let's convert the molarity of 0.5 M HCl to 0.5 mol HCl per liter. This will make unit cancellation easier.

The moles of solute or HCl are unknown, so we can use x. Now, we can substitute all known values into the formula.

0.5 \ mol \ HCl /L  = \frac {x}{0.8 \ L}

Since we are solving for the moles of solute (x), we must isolate the variable. It is being divided by 0.8 liters. The inverse of division is multiplication, so we multiply both sides by 0.8 L.

0.8 \ L *0.5 \ mol \ HCl /L  = \frac {x}{0.8 \ L} *0.8 \ L

0.8 \ L *0.5 \ mol \ HCl /L=x

The units of liters (L) cancel.

0.8 * 0.5 \ mol \ HCl= x

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