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svlad2 [7]
3 years ago
10

Write the overall equation for the conversion of pyruvate to acetyl coa. express your answer as a chemical equation.

Chemistry
1 answer:
Schach [20]3 years ago
5 0
 the overall  equation  for the conversation of pyruvate  to  acetyl COA  is as below

CH3COO-COO-  + NAD+  + HS-COA = ch3-COO-S -COA +NADH +CO2

The oxidation of pyruvate led to a conversation  of NAD+  to NADH and  produces acetyl COA  and CO2
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Which are forms of frozen water? Check all that apply. dew frost hail rain sleet
MariettaO [177]

When moist air cools below its dew point on a cold surface it forms dew. It is in the liquid state.

Rain is again a form of precipitation in which water is in the liquid state.

When air temperature is below freezing, the precipitation that results is referred to as frost. Hail is a form of precipitation in the ice balls whereas as sleet is a mixture of rain and snow.

Ans: Forms of frozen water- frost, hail and sleet

7 0
3 years ago
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Commercial cold packs often contain solid NH4NO3 and a pouch of water. The temperature of the pack drops as the NH4NO3 dissolves
Yanka [14]

Answer: b. \Delta H_{soln} is positive and \Delta S_{soln} is positive.

Explanation:-

As the temperature of the pack drops, the energy has been absorbed from the pack for dissolution of NH_4NO_3 in water. Thus as the energy has been absorbed in the reaction, the reaction is endothermic and the change in enthalpy i.e. \Delta H_{soln} is positive.

The entropy is the measure of degree of randomness. The entropy increases when the randomness increases and the entropy decreases when the randomness decreases. When a substance dissolves in water, it dissociate into ions and hence the randomness increases thus the change in entropy i.e. \Delta S_{soln}  is positive.

NH_4NO_3\rightarrow NH_4^++NO_3^-

7 0
3 years ago
The s subshell can hold up to two electrons in an atom. True or False
marshall27 [118]
True but this can vary 
5 0
3 years ago
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What causes polar bonds
yulyashka [42]

Answer:

Bonds are polar when one element in a compound is more electronegative than the other. This creates a dipole in the molecule where one end of the molecule is partially positive and one end is partially negative

Explanation:

8 0
3 years ago
A 33.0−g sample of an alloy at 93.00°C is placed into 50.0 g of water at 22.00°C in an insulated coffee-cup calorimeter with a h
Lostsunrise [7]

Answer:

THE SPECIFIC HEAT OF THE ALLOY IS 0.9765 J/g K

Explanation:

Mass of alloy = 33 g

Initial temperature of alloy = 93°C

Mass of water = 50 g

Initail temp. of water = 22 °C

Heat capacity of calorimeter = 9.20 J/K

Final temp. = 31.10 °C

specific heat of alloy = unknown

specific heat capacity of water = 4.2 J/g K

Heat = mass * specific heat * change in temperature = m c ΔT

Heat = heat capcity * chage in temperature = Δ H * ΔT

In calorimetry;

Heat lost by the alloy = Heat gained by water + Heat of the calorimeter

                     mc ΔT = mcΔT + Heat capacity * ΔT

33 * C * ( 93 - 31.10) = 50 * 4.2 * ( 31.10 -22) + 9.20 * ( 31.10 -22)

33 * C * 61.9 = 50 * 4.2 * 9.1 + 9.20 * 9.1

2042.7 C = 1911 + 83,72

C = 1911 + 83.72 / 2042.7

C = 1994.72 /2042.7

C =0.9765 J/g K

The specific heat of the alloy is 0.9765 J/ g K

5 0
3 years ago
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