Answer:
C₆H₁₂O₆ (glucose)
A molecular substance.
Explanation:
C₆H₁₂O₆ does not dissociate. It is not a ionic type.
There is no metal in the compound, it is not a metallic type.
Glucose is an organic molecule, a type of carbohidrate, the most common from the monosaccharides type.
Answer:
25.6 %.
Explanation:
- To calculate the % of Cl in KClO₄:
<em>% Cl = [Atomic mass of (Cl)/molar mass of KClO₄] x 100</em> = [(35.5 g/mol)/(138.55 g/mol)] x 100 = <em>25.62 % ≅ 25.6 %.</em>
Answer:
-0.85KJ
Explanation:
Given N2(g) + H2(g) <--->2NH3(g)
Kp =[ P(NH3)]²/[P(H2)]³[P(N2)]
Where P is the pressure of the gas
P(H2)b= P(N2) = 125atm
P(NH3) = 200atm
Kp = 2²/(125)³(125)
Kp = 2.048 ×10^-6
∆G = -RTlnKp
R =0.008314 J/Kmol
T = 25 +273/= 298k
= 8.314 ×10^-3 × 298 × ln(2.048 ×10^-6)
= -0.008314 × 298 × (-13.099)
= 32.45KJ
∆G = ∆G° + RTlnKp
∆G = -33.3 + 32.45
∆G = -0.85KJ or -850J
Answer:
Hexanoic acid is formed as insoluble product
Explanation:
- In aqueous sodium hydroxide, methyl ester of hexanoic acid hydrolyzes to produce soluble sodium hexanoate salt.
- Upon addition of aqueous HCl, hexanoate ion is protonated to produce hexanoic acid which is insoluble in water.
- Hence, upon acidification of hydrolysis solution, two separate layers (organic and aqueous) are formed.
- Reaction are shown below.
The Lewis dot diagram structure for hydrogen cyanide would be the following:
H - C --- N
--- = triple bond.
