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3 years ago

11

During a science investigation, a sample of matter breaks down into two kinds of atoms. Was the original sample an element or a

compound? Explain.

1 answer:

nevsk [136]3 years ago

3 0

The original sample was a compound because it was composed of two different elements and was not purely one element

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When preparing the diazonium salt, the solution is tested with potassium iodide-starch paper. a positive test is the immediate f

Dahasolnce [82]

KI-starch paper allows the detection of strong oxidizers such as nitrite. It is used here to control diazotization of 4-nitroaniline. Nitrite oxidizes potassium iodide in order to form elemental iodine which reacts with starch to a blue-violet complex. With KI-starch paper, enough sodium nitrite is added to produce nitrous acid, which <span>then will react with 4-nitroaniline to form a diazonium salt.</span>

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3 years ago

Đốt cháy hoàn toàn 0,06 mol hỗn hợp X gồm hai amin no, đơn chức, mạch hở và một hiđrocacbon cần

n200080 [17]

Ban vo gay wiwidhta ay A 8 95

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3 years ago

Other than reducing greenhouse gas emissions, why would an entity switch to an alternative energy solution

Alika [10]

Answer:

renewable energy sources such as solar and wind DONT emit carbon dioxide and other greenhouse gases that contribute to global warming

Explanation:

8 0

2 years ago

Which statement correctly describes metallic bonds?

lions [1.4K]

Answer: D

Explanation:

the atom of the metal loses one electron which becomes delocalised and is attragted by the positive nucleus leading to formation of metallic bond.

5 0

3 years ago

Given that kb for c6h5nh2 is 1.7 × 10-9 at 25 °c, what is the value of ka for c6h5nh3 at 25 °c?

lina2011 [118]

Answer: $k_a$ for $C_6H_5NH_3^+$ at 25°C is $0.588\times 10^{-4}$

Explanation: We are given $k_b$ of $C_6H_5NH_2$ at 25°C which is $1.7\times 10^{-9}$

To calculate the $k_a$ of $C_6H_5NH_3^+$ , we use the formula:

$k_w=k_a\times k_b$

$k_w\text{ at }25^o=1\times 10^{-14}$

Putting values in above equation, we get:

$1\times 10^{-14}=k_a\times (1.7\times 10^{-9})\\k_a=0.588\times 10^{-5}$

7 0

3 years ago