Which of these determines an objects ability to sink or float in water?

a person jogs eight complete laps around a 400-m track in a total time of 15.1 min .calculate the average speed, in m/s .

valentinak56 [21]

The average speed in m/s of a person that jogs eight complete laps around a 400m track in a total time of 15.1 min is 0.44m/s.

<h3>How to calculate average speed?</h3>

Average speed of a moving body can be calculated by dividing the distance moved by the time taken.

Average speed = Distance ÷ time

According to this question, a person jogs eight complete laps around a 400m track in a total time of 15.1 min. The average speed is calculated as follows:

15.1 minutes in seconds is as follows = 906 seconds

Average speed = 400m ÷ 906s

Average speed = 0.44m/s

Therefore, the average speed in m/s of a person that jogs eight complete laps around a 400m track in a total time of 15.1 min is 0.44m/s.

Learn more about average speed at: brainly.com/question/12322912

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6 0

1 year ago

Which of the following are examples of projectile motion??

sashaice [31]

B and C! I like to think of projectile motion as a motion that doesn’t go in a straight line, it has two directions.

6 0

4 years ago

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Particles q1 = -53.0 uc, q2 = +105 uc, and

Nimfa-mama [501]

Answer:

$-180.38\ \text{N}$

Explanation:

$q_1=-53\ \mu\text{C}$

$q_2=105\ \mu\text{C}$

$q_3=-88\ \mu\text{C}$

r = Distance between the charges

$r_{12}=0.5\ \text{m}$

$r_{23}=0.95\ \text{m}$

$r_{13}=1.45\ \text{m}$

k = Coulomb constant = $9\times 10^9\ \text{Nm}^2/\text{C}^2$

Net force is given by

$F=F_{12}+F_{13}\\\Rightarrow F=\dfrac{kq_1q_2}{r_{12}^2}+\dfrac{kq_1q_3}{r_{13}^2}\\\Rightarrow F=kq_1(\dfrac{q_2}{r_{12}^2}+\dfrac{q_3}{r_{13}^2})\\\Rightarrow F=9\times 10^9\times (-53\times 10^{-6})(\dfrac{105\times 10^{-6}}{0.5^2}+\dfrac{-88\times 10^{-6}}{1.45^2})\\\Rightarrow F=-180.38\ \text{N}$

The force on the particle $q_1$ is $-180.38\ \text{N}$ .

8 0

3 years ago

A baseball team is practicing throwing balls vertically upward to test their throwing arms. A player manages to throw a ball tha

Nitella [24]

We can solve this problem using the law of conservation of energy.
This law states that energy in a closed system must stay same.
That means that the energy of a ball leaving the hand and the energy of a ball when it reaches its maximum height must be the same.
The energy of a ball leaving the players hand is kinetic energy:
$E_k=\frac{mv^2}{2}$
The energy when the ball reaches its maximum height ( and has zero velocity) is potential energy in a gravitational field:
$E_p=mgh$
As said before these energies must be the same, and that allows us to find the initial speed:
$E_k=E_p\\
\frac{mv^2}{2}=mgh\\
v^2=2gh\\
v=\sqrt{2gh}$
When we plug in all the number we get that $v=14\frac{m}{s}$

7 0

3 years ago

Jennifer is making a collage using her favorite photos. She wants to cover the collage with something that allows her to see the

Karolina [17]

B.) A transparent material

4 0

3 years ago

Read 2 more answers