Answer:
v = 6.06 m/s
Explanation:
In order for the rider to pass the top of the loop without falling, his weight must be equal to the centripetal force:

where,
v = minimum speed of motorcycle at top of the loop = ?
g = acceleration due to gravity = 9.8 m/s²
r = radius of the loop = diameter/2 = 7.5 m/2 = 3.75 m
Therefore, using these values in equation, we get:

<u>v = 6.06 m/s</u>
Option B. By not being 100% efficient, it shows that some energy is lost to unusable or unwanted sources
Given,
The momentum of the object A before the collision, p₁ =80 Ns
The momentum of the object B before the collision, p₂=-30 Ns
Given that the objects stick together after the collision.
From the law of conservation of momentum, the total momentum of a system should always remain the same. Thus the total momentum of the objects before the collision must be equal to the total momentum of the objects after the collision.
Thus,

Where p is the total momentum of the system at any instant of time.
On substituting the known values,

Therefore the total momentum of the system is 50 Ns
Thus the momentum of the object AB after the collision is 50 Ns
C. Figure 11 and figure 1v are both compounds