All categories

4 years ago

Calculate the work done by a 47 N force pushing a pencil 0.26 m. Question 1 options: A. 0.005 J B. 12.2 J C. 180.77 J

Physics

2 answers:

lana [24]4 years ago

6 0

Hello There!

Answer is provided in the image attached.

Have a great day!

vfiekz [6]4 years ago

4 0

The work done by a force when moving an object is given by:
$W=Fd$
where W is the work, F is the force and d the displacement of the object.
Therefore, using $F=47~N$ and $d=0.26~m$ , we get a total work of
$W=Fd=47~N \cdot 0.26~m=12.22~J$

You might be interested in

What caused the blackout in Canada?

Maru [420]

Answer:

Hello, the tripping of a 230-kilovolt transmission line.

Explanation:

the tripping of a 230-kilovolt transmission line near Ontario, Canada, at 5:16 p.m., which caused several other heavily loaded lines also to fail. Hopefully this helps you find what your looking for!.

7 0

3 years ago

Law of Conservation of Energy.

Tems11 [23]

Energy cannot be created nor be destroyed

3 0

4 years ago

How can you turn off a magnetic field produced by an electrical current?

aleksklad [387]

Answer:By turning the electrical current off

Explanation:Trust me I took the test

6 0

3 years ago

Read 2 more answers

Each bat can produce different frequencies of ultrasound. Explain why this is useful if there are many bats hunting together.

Crazy boy [7]

Answer: Although low frequency sound travels further than high-frequency sound, calls at higher frequencies give the bats more detailed information--such as size, range, position, speed and direction of a prey's flight. Thus, these sounds are used more often.

Explanation:

6 0

3 years ago

calculate earths velocity of approach toward the sun when earth in its orbit is at an extremum of the latus rectum through the s

IceJOKER [234]

Answer:

Hello your question is incomplete below is the complete question

Calculate Earths velocity of approach toward the sun when earth in its orbit is at an extremum of the latus rectum through the sun, Take the eccentricity of Earth's orbit to be 1/60 and its Semimajor axis to be 93,000,000

answer : V = 1.624* 10^-5 m/s

Explanation:

First we have to calculate the value of a

a = 93 * 10^6 mile/m * 1609.344 m

= 149.668 * 10^8 m

next we will express the distance between the earth and the sun

$r = \frac{a(1-E^2)}{1+Ecos\beta }$ --------- (1)

a = 149.668 * 10^8

E (eccentricity ) = ( 1/60 )^2

$\beta$ = 90°

input the given values into equation 1 above

r = 149.626 * 10^9 m

next calculate the Earths velocity of approach towards the sun using this equation

$v^2 = \frac{4\pi^2 }{r_{c} }$ ------ (2)

Note :

Rc = 149.626 * 10^9 m

equation 2 becomes

( $V^2 = (\frac{4\pi^{2} }{149.626*10^9})$

therefore : V = 1.624* 10^-5 m/s

4 0

4 years ago