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guajiro [1.7K]
3 years ago
14

Can someone plss help me asap !!

Chemistry
1 answer:
ludmilkaskok [199]3 years ago
6 0
I think the answer is barium
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What is 21.97 to three significant figures
antiseptic1488 [7]

21.97

Sig Figs

   4

Decimals

   2

Scientific Notation

   2.197 × 101

Answer:

Explanation:

7 0
3 years ago
Read 2 more answers
How many chlorine particles are in 4.5 moles in sig figs
Mariana [72]

Answer:

2.71×10²⁴ particles

Explanation:

Applying Avogadro's constant

Avogadro's constant states that, The number of specified particles contained in a mole of a substance is equal to 6.02×10²³.

From the question,

If one mole of chlorine contains a particle of  6.02×10²³,

Therefore,

4.5 moles of chlorine will contain a particle of (4.5× 6.02×10²³)

⇒ 27.09×10²³

Hence the number of particle contained in 4.5 moles of chlorine ≈ 2.71×10²⁴ particles

6 0
3 years ago
A reaction occurs when a solid X is placed into a solution Y as a result the temp of the new solution increases by 3.C the temp
saw5 [17]

Answer:

Fneneicjcd

Explanation:

4 0
4 years ago
What is the density of a 0.5cm3 nugget of gold that has a mass<br> of 10g?
Rom4ik [11]

Answer:

The density is 20 g/cm3

Explanation:

The density (δ) is the ratio between the mass and the volume of a compound:

δ=m/v= 10 g/0,5 cm3=<em>20 g/cm3</em>

5 0
4 years ago
if 45.0 ml of 1.50 M Ca(OH)2 are needed to neutralize 25.0 ml of HI of unknown concentration, what is the molarity of the HI?
ipn [44]

Answer:

M of HI = 5.4 M.

Explanation:

  • We have the rule: at neutralization, the no. of millimoles of acid is equal to the no. of millimoles of the base.

<em>(XMV) acid = (XMV) base.</em>

where, X is the no. of (H) or (OH) reproducible in acid or base, respectively.

M is the molarity of the acid or base.

V is the volume of the acid or base.

<em>(XMV) HI = (XMV) Ca(OH)₂.</em>

For HI; X = 1, M = ??? M, V = 25.0 mL.

For Ca(OH)₂, X = 2, M = 1.5 M, V = 45.0 mL.

<em>∴ M of HI = (XMV) Ca(OH)₂ / (XV) HI</em> = (2)(1.5 M)(45.0 mL) / (1)(25.0 mL) = <em>5.4 M.</em>

6 0
4 years ago
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