Answer:
2.71×10²⁴ particles
Explanation:
Applying Avogadro's constant
Avogadro's constant states that, The number of specified particles contained in a mole of a substance is equal to 6.02×10²³.
From the question,
If one mole of chlorine contains a particle of 6.02×10²³,
Therefore,
4.5 moles of chlorine will contain a particle of (4.5× 6.02×10²³)
⇒ 27.09×10²³
Hence the number of particle contained in 4.5 moles of chlorine ≈ 2.71×10²⁴ particles
Answer:
The density is 20 g/cm3
Explanation:
The density (δ) is the ratio between the mass and the volume of a compound:
δ=m/v= 10 g/0,5 cm3=<em>20 g/cm3</em>
Answer:
M of HI = 5.4 M.
Explanation:
- We have the rule: at neutralization, the no. of millimoles of acid is equal to the no. of millimoles of the base.
<em>(XMV) acid = (XMV) base.</em>
where, X is the no. of (H) or (OH) reproducible in acid or base, respectively.
M is the molarity of the acid or base.
V is the volume of the acid or base.
<em>(XMV) HI = (XMV) Ca(OH)₂.</em>
For HI; X = 1, M = ??? M, V = 25.0 mL.
For Ca(OH)₂, X = 2, M = 1.5 M, V = 45.0 mL.
<em>∴ M of HI = (XMV) Ca(OH)₂ / (XV) HI</em> = (2)(1.5 M)(45.0 mL) / (1)(25.0 mL) = <em>5.4 M.</em>
