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nadezda [96]
3 years ago
10

A car traveling on a straight road at 15.0 meters per second accelerates uniformly to a speed of 21.0 meters per second in 12.0

seconds. The total distance traveled by the car in this 12.0-second time interval is _______.(1) 36.0 m (3) 216 m(2) 180. m (4) 252 m
Physics
1 answer:
oksano4ka [1.4K]3 years ago
8 0
<h2>Option 3,  216 m is the correct answer.</h2>

Explanation:

We have initial velocity, u = 15 m/s

Time, t = 12 seconds

Final velocity, v = 21 m/s

We have equation of motion v = u + at

Substituting

                     21 = 15 + a x 12

                       a = 0.5 m/s²

Now we have equation of motion v² = u² + 2as

                           21² = 15² + 2 x 0.5 x s

                            s = 216 m

       Displacement = 216 m

Option 3,  216 m is the correct answer.

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      The distance from the binoculars is    d = 18cm = \frac{18}{100} = 0.18m

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Without the 8 X binoculars the  angle made with the angular size of the object  is mathematically represented as

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