Answer:
The four are Ll
The four will have long feathers
Explanation:
A Punnett square is a graphical representation of all possible genotypes of an offspring that is likely to arise from a particular cross or breeding event. To create a Punnett square, knowledge of the genetic composition of the parents is highly required. The two things a Punnett square can tell you are the genotypes and phenotypes of the offspring. In its simplest form, the Punnett square consists of a square divided into four quadrants. A Punnett square allows the prediction of the percentages of phenotypes in the offspring of a cross from known genotypes.
The genotypes of the four offsprings are Ll, Ll, Ll and Ll. This implies that they are all heterozygous. They will all have long feathers since the long feather (L) is dominant in all the species. In terms of phenotype, they will all have long feathers.
Answer:
n, the number of moles of gas is the same
Explanation:
PV = n RT if P and V and T and R are the same , the n must be the same
n = numer of moles
According to markovnikov's rule of the electrophilic addition to an alkene, the electrophile, usually a proton, is more likely to add to the less-substituted carbon in a double bond.
With additional substituents present in this configuration, the intermediate carbocation is stabilised by being located on the more-substituted carbon.
The nucleophile will then end up in a double bond on the more-substituted carbon in a reaction that follows Markovnikov's rule.The outcome of some addition reactions is described by Markovnikov's rule or Markownikoff's rule in organic chemistry. Vladimir Markovnikov, a Russian scientist, created the rule in 1870.
To learn more about Markovnikov's rule
brainly.com/question/14529644
#SPJ4
Answer:
moles of carbon
Explanation:
1 trillion =
Avogadro number :It is the number of particles that are present in 1 mole of substance.
So,
atoms = 1 mole carbon
1 atom =
mole
1 trillion atom =
mole
mol
Two significant figure
moles of carbon
Answer:
Explanation:
Hello,
In this case, we are asked to compute the by mass percent for the given 3.2 g of ethylene glycol in 43.5 g of water. In such a way, since the by mass percent is computed as follows:
Whereas the solute is the ethylene glycol and the solvent the water, therefore we obtain:
Best regards.