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3 years ago

Semiconductor pn junction diode and zener diode quiz questions

1 answer:

7 0

1.) A semiconductor is a device whose conductivity lies between the conductivity of the conductors and the insulators.

2.) A Zener diode is a semiconductor device made of silicon that allows current to flow in both directions.

<h3>What is a semiconductor?</h3>

A semiconductor is a device whose conductivity lies between the conductivity of the conductors and the insulators.

Due to the inclusion of an impurity or temperature effects, a solid substance with conductivity between that of an insulator and that of most metals. Semiconductor devices, particularly silicon devices, are key components of most electronic circuits.

Zener diode:-

A Zener diode is a semiconductor device made of silicon that allows current to flow in both directions.

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What is the first step in the problem-solving process, as well as in the engineering design process?

DENIUS [597]

Answer:

C. Brainstorm

Explanation:

<em>Brainstorming refers to thinking and developing ideas and solutions to problems</em>. It involves a free-thinking approach and putting oneself in the context of the problem you are attempting to solve. You can use the empathy maps to combine ideas from interviewing other people on the same. This stage is followed by defining the problem, concept generation, developing a solution, constructing a testing a prototype, evaluating the solution and finally presenting the solution.

Answer choice A is incorrect because it is the last stage .

Answer choice B is incorrect because it is the second stage.

Answer choice D is incorrect because it is step 5 and 6.

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4 years ago

It is given that 50 kg/sec of air at 288.2k is iesntropically compressed from 1 to 12 atm. Assuming a calorically perfect gas, d

denis23 [38]

The exit temperature is 586.18K and compressor input power is 14973.53kW

Data;

Mass = 50kg/s
T = 288.2K
P1 = 1atm
P2 = 12 atm

<h3>Exit Temperature </h3>

The exit temperature of the gas can be calculated isentropically as

$\frac{T_2}{T_1} = (\frac{P_2}{P_1})^\frac{y-1}{y}\\ y = 1.4\\ C_p= 1.005 Kj/kg.K\\$

Let's substitute the values into the formula

$\frac{T_2}{T_1} = (\frac{P_2}{P_1})^\frac{y-1}{y} \\\frac{T_2}{288.2} = (\frac{12}{1})^\frac{1.4-1}{1.4} \\ T_2 = 586.18K$

The exit temperature is 586.18K

<h3>The Compressor input power</h3>

The compressor input power is calculated as

$P= mC_p(T_2-T_1)\\P = 50*1.005*(586.18-288.2)\\P= 14973.53kW$

The compressor input power is 14973.53kW

Learn more on exit temperature and compressor input power here;

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3 years ago

A system consists initially of nA moles of gas A at pressure p and temperature T and nB moles of gas B separate from gas A but a

Volgvan

Answer:

A) б = - R ( nA In Ya - nB In Yb )

B) s2 = ( nA + nB ) s( T,P )

C) No entropy will be produced

Explanation:

A) assuming ideal gas behavior the expression for entropy produced

for a closed system : s2 - s1 = б

where : s1 ( initial entropy ) = nA sA ( T, P ) + nB sB ( T, P )

s2 ( final entropy ) = nA sA ( T, YaP ) + nB sB ( T, YbP )

∴ б = - R ( nA In Ya - nB In Yb )

B) Given that

Ya and Yb are less than 1 respectively, hence the value of б = positive

also assuming the gases are identical

s2 = ( nA + nB ) s( T,P )

C) No entropy will be produced when same gas at same temperature and same pressure are mixed

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3 years ago

3. Aqueous cleaners are

allsm [11]

D) O Water - Based Is the 1000000000000000000% correct answer

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3 years ago

This question is in C programming.Write a loop that sets newScores to oldScores shifted once left, with element 0 copied to the

andriy [413]

Answer:

Replace

/* Your solution goes here */

with the following;

for (i = 0; i < SCORES_SIZE - 1; i++) {

newScores[i] = oldScores[i + 1];

}

newScores[SCORES_SIZE - 1] = oldScores[0];

The full program becomes

#include

int main(void) {

const int SCORES_SIZE = 4;

int lowerScores[SCORES_SIZE];

int i;

for (i = 0; i < SCORES_SIZE; ++i) {

scanf("%d", &(lowerScores[i]));

}

for (i = 0; i < SCORES_SIZE - 1; i++) {

newScores[i] = oldScores[i + 1];

}

newScores[SCORES_SIZE - 1] = oldScores[0];

for (i = 0; i < SCORES_SIZE; ++i) {

printf("%d ", lowerScores[i]);

}

printf("\n");return 0;

}

What the included code segment does it that;

for (i = 0; i < SCORES_SIZE - 1; i++) {

newScores[i] = oldScores[i + 1];

}

The above assigns the values of array oldScores to newScores starting with the second element of array oldScores till the last.

newScores[SCORES_SIZE - 1] = oldScores[0];

The above line then assigns the first element of oldScores to the first element of newScores array

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4 years ago