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ss7ja [257]
3 years ago
7

In a 100-m race, the winner is timed at 11.2 s. The second-place finisher’s time is 11.6 s. How far is the second-place finisher

behind the winner when she crosses the finish line? Assume the velocity of each runner is constant throughout the race.
Physics
1 answer:
Veronika [31]3 years ago
3 0

Answer:

d = 3.45 m

Explanation:

given,

distance, d = 100 m

time of winner = 11.2 s

time of finisher = 11.6 s

distance between them when winner finish race

speed of winner

s_1 = \dfrac{d}{t_1}

s_1 = \dfrac{100}{11.2}

 s₁ = 8.93 m/s

speed of runner up

s_2 = \dfrac{d}{t_2}

s_2= \dfrac{100}{11.6}

 s₂= 8.62 m/s

difference in time = t₂ - t₁ = 11.6 - 11.2 = 0.4 s

distance between them

d =  s₂ x t

d = 8.62 x 0.4

d = 3.45 m

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v2 = [46.08 N*s + 0.310*14.5 N*s] / 95.69 k = 0.529 m/s


3 0
3 years ago
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