They are different by a phase shift of pi/2
Answer:
2.29 g of N2
Explanation:
We have to start with the <u>chemical reaction</u>:

The next step is to <u>balance the reaction</u>:

We can continue with the <u>mol calculation</u> using the molar mass of
(65 g/mol), so:

Now, with the<u> molar ratio</u> between
and
we can <u>calculate the moles</u> of
(2:3), so:
With the molar mass of
we can <u>calculate the grams</u>:
I hope it helps!
Answer:
Total number of ATP molecules generated from a 32-carbon fatty acid = 206 ATP molecules
Explanation:
A 32 carbon fatty acid which undergoes complete beta-oxidation assuming that the fatty acid is fully saturated will pass through the beta-oxidation cycle 14 times to produce the following:
15 molecules of acetylCoA, 14 molecules of FADH₂, and 14 molecules of NADH.
Each of the 15 acetylCoA molecules can be further oxidized in the citric acid cycle to yield the following: 15 × 3 NADH; 15 × 1 FADH₂, and 15 ATP molecules from the substrate level phosphorylation occuring at the succinylCoA synthetase catalyzed-reaction.
Total FADH₂ produced = 15 + 14 = 29 molecules of FADH₂
Total NADH produced = 45 + 14 = 59 molecules of NADH
The FADH₂ and NADH will each donate a pair of electrons to the electron transfer flavoprotein and mitochondrial NADH dehydrogenase respectively of the electron transport chain, and about 1.5 and 2.5 molecules of ATP are generated respectively when these electrons are transfered to molecular oxygen.
Thus, number of molecules of ATP generated by 29 molecules of FADH₂ = 1.5 × 29 = 43.5 molecules of ATP.
Number of molecules of ATP generated by 59 molecules of NADH = 2.5 × 59 = 147.5
Sum of ATP generated from FADH₂ and NADH = 43.5 + 147.5 = 191 ATP molecules
Total number of ATP molecules generated = 191 + 15 = 206 ATP molecules
Total number of ATP molecules generated from a 32-carbon fatty acid = 206 ATP molecules
Answer : The change in entropy is 
Explanation :
Formula used :

where,
= change in entropy = ?
m = mass of water = 1.00 kg
= heat of vaporization of water = 
T = temperature = 
Now put all the given values in the above formula, we get:


Therefore, the change in entropy is 
Answer:
pH = 6.8124
Explanation:
We know pH decreases with increase in temperature.
At room temperature i.e. 25⁰c pH of pure water is equal to 7
We know
Kw = [H⁺][OH⁻]...............(1)
where Kw = water dissociation constant
At equilibrium [H⁺] = [OH⁻]
So at 37⁰c i.e body temperature Kw = 2.4 × 10⁻¹⁴
From equation (1)
[H⁺]² = 2.4 × 10⁻¹⁴
[H⁺] = √2.4 × 10⁻¹⁴
[H⁺] = 1.54 × 10⁻⁷
pH = - log[H⁺]
= - log{1.54 × 10⁻⁷}
= 6.812