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3 years ago

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A car traveling at a velocity of 40 m/s accelerates at 5 m/s/s for 10 seconds. What is the car's final velocity?

1 answer:

Papessa [141]3 years ago

8 0

Answer:

<h3>The answer is 90 m/s</h3>

Explanation:

To find the final velocity of an object given it's initial velocity , time taken and it's acceleration we use the formula

<h3>v = u + at </h3>

where

v is the final velocity

u is the initial velocity

t is the time taken

a is the acceleration

From the question

u = 40 m/s

t = 10s

a = 5 m/s²

We have

v = 40 + 5(10) = 40 + 50

We have the final answer as

<h3>90 m/s</h3>

Hope this helps you

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A parallel-plate capacitor stores charge Q. The capacitor is then disconnected from its voltage source, and the space between th

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Answer:

The relationship between the initial stored energy $PE_{i}$ and the stored energy after the dielectric is inserted $PE_{f}$ is:

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Explanation:

A parallel plate capacitor with $C_{o}$ that is connected to a voltage source $V_{o}$ holds a charge of $Q_{o} =C_{o} V_{o}$ . Then we disconnect the voltage source and keep the charge $Q_{o}$ constant . If we insert a dielectric of $\kappa=2$ between the plates while we keep the charge constant, we found that the potential decreases as:

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The stored energy without the dielectric is

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The stored energy after the dielectric is inserted is:

$PE_{f}=\frac{1}{2}\frac{Q^{2}}{C}=\frac{1}{2}CV^{2}$

If we replace in the above equation the values of V and C we get that

$PE_{f}=\frac{1}{2}\kappa\ C_{o}(\frac{V_{o}}{\kappa})^{2}=\frac{1}{\kappa}(\frac{1}{2}C_{o}V_{o}^{2})$

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3 years ago

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Answer:

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