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ankoles [38]
2 years ago
14

Which will have the lowest boiling point?

Chemistry
2 answers:
In-s [12.5K]2 years ago
8 0

Some of the solutions exhibit colligative properties. These properties depend on the amount of

solute dissolved in a solvent. These properties include freezing point depression, boiling

point elevation, osmotic pressure and vapor pressure lowering. From the given choices, the correct answer is the first option. Pure water will have the lowest boiling point because there are no solute particles to change the boiling point of water while other options will have an elevated boiling point because of the solute.

Read more on Brainly.com - brainly.com/question/1437052#readmore

Zina [86]2 years ago
4 0

Answer: A.   pure water

Explanation:

\Delta T_b=i\times k_f\times m

\Delta T_b = change in boiling point

i = Van'T Hoff factor  

k_f = freezing point constant

m = molality

1. For pure water

, i= 1 as it is a non electrolyte and does not dissociate.

2. For 0.5M NaCl

NaCl\rightarrow Na^+Cl^-

, i= 2 , as it is a electrolyte and dissociate to give 2 ions and concentration will be (0.5+0.5)=1M[/tex]

3. For 1M NaCl

NaCl\rightarrow Na^+Cl^-

, i= 2 , as it is a electrolyte and dissociate to give 2 ions and concentration will be (1+1)=2M[/tex]

4. For 2M NaCl

NaCl\rightarrow Na^+Cl^-

, i= 2 , as it is a electrolyte and dissociate to give 2 ions and concentration will be (2+2)=4M[/tex]

Thus as vant hoff factor is lowest for pure water and thus the boiling point will be lowest.

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Balloon has a volume of 600-ml at temperature of 360 K. If the temperature of
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Answer:

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Explanation:

This question asks us to find the volume, given another volume and 2 temperatures in Kelvin. Based on this information, we must be using Charles's Law and the formula. Remember, his law states the volume of a gas is proportional to the temperature.

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where V₁ and V₂ are the first and second volumes, and T₁ and T₂ are the first and second temperature.

The balloon has a volume of 600 milliliters and a temperature of 360 K, but the temperature then drops to 250 K. So,

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Substitute the values into the formula.

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Since we are solving for the second volume when the temperature is 250 K, we have to isolate the variable V₂. It is being divided by 250 K. The inverse o division is multiplication, so we multiply both sides by 250 K.

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The units of Kelvin cancel, so we are left with the units of mL.

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1. Calculate the attractive bonding force for NaF and for MgO when the ions just touch. Based on the attractive bonding force, w
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Answer:

The attractive force is negative and MgO has a higher melting point

Explanation:

From Couloumb's law:

Energy of interaction, E = k \frac{q1q2}{r}

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The melting point of ionic compounds is determined by 1. charge on the ions 2. size of ions. while NaF has smaller charges (+1 and -1), MgO (+2 and -2) has larger charges and greater combined atomic radii. This implies that the compound with greater force would have a higher melting point.

Hence the compound MgO would have a higher melting point than NaF.

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