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2 years ago

7

a two eyed minion homozygous is married to a one eyed minion. They have 8 children. How many of those children will have two eye

s

1 answer:

solniwko [45]2 years ago

4 0

3/8ths im not sure if this is correct ! :)

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An atom in the ground state has a collision with an electron, then emits a photon with a wavelength of 1240 nm. What conclusion

anyanavicka [17]

Answer:

attached below is the free body diagram of the missing illustration

Initial kinetic energy of the electron = 3 eV

Explanation:

The conclusion that can be drawn about the kinetic energy of the electron is

$E_{e} = E_{3} - E_{1}$

E $_{e}$ = initial kinetic energy of the electron

E $_{1}$ = -4 eV

E $_{3}$ = -1 eV

insert the values into the equation above

$E_{e}$ = -1 -(-4) eV

= -1 + 4 = 3 eV

6 0

2 years ago

The maximum wavelength an electromagnetic wave can have and still eject an electron from a copper surface is 264 nm .What is the

Tamiku [17]

Answer:

4.71 eV

Explanation:

For an electromagnetic wave with wavelength

$\lambda=264 nm = 2.64\cdot 10^{-7} m$

the energy of the photons in the wave is given by

$E=\frac{hc}{\lambda}=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{2.64\cdot 10^{-7}m}=7.53\cdot 10^{-19} J$

where h is the Planck constant and c the speed of light. Therefore, this is the minimum energy that a photon should have in order to extract a photoelectron from the copper surface.

The work function of a metal is the minimum energy required by the incident light in order to extract photoelectrons from the metal's surface. Therefore, the work function corresponds to the energy we found previously. By converting it into electronvolts, we find:

$E=\frac{7.53\cdot 10^{-19} J}{1.6\cdot 10^{-19} J/eV}=4.71 eV$

3 0

2 years ago

Elena pulls a sled with her younger brother and sister across the snow covered yard. Then she pulls the same sled across a smoot

mylen [45]

The answer is B.
Hope this helps!

5 0

3 years ago

A horizontal force of 100 N is used to pull a crate, which weighs 500 N, at constant velocity across a horizontal floor. What is

Ilya [14]

Answer:

0.2

Explanation:

Horizontal force=100N

Weight of crate=500 N

We have to find the coefficient of kinetic friction.

Normal ,N=Weight=500N

Horizontal force, $F_x=\mu_kN$

Where $F_x$ =Horizontal force

N=Normal force

$\mu_k$ =Coefficient of kinetic friction

Substitute the values in the formula

$100=\mu_k(500)$

$\mu_k=\frac{100}{500}=0.2$

Hence, the coefficient of kinetic friction =0.2

8 0

2 years ago

If an electric wire is allowed to produce a magnetic field no larger than that of the earth (0.50×10−4t) at a distance of 12 cm

Studentka2010 [4]

The magnetic field generated by a wire carrying a current I is:
$B(r) = \frac{\mu_0 I}{2 \pi r}$
where r is the distance at which the magnetic field is measured, and $\mu_0 = 4 \pi \cdot 10^{-7} NA^{-2}$ is the magnetic permeability in vacuum.

The problem says that the magnetic field at a distance r=12 cm=0.12 m from the wire must be no larger than $B=0.5 \cdot 10^{-4}T$ . Substituting these values, we can find the maximum value of the current I that the wire can carry:
$I= \frac{2 \pi r B}{\mu _0} = \frac{2 \pi (0.12 m)(0.5 \cdot 10^{-4}T)}{ 4 \pi \cdot 10^{-7} NA^{-2}}= 30 A$

4 0

3 years ago