Answer:
a) FeCl2, FeCl3, MgCl2, KClO2.
KClO2 --> K+ + ClO2-; ClO2- will hydrolyse to form HClO +OH-
Mg+2, Fe+2 and Fe+3 ions will form acidic solutions, since theyfom slightly amount of
Mg+2 + 2H2O <-> Mg(OH)2 + 2H+
Fe+2 + 2H2O <-> Fe(OH)2 + 2H+
Fe+3 + 3H2O <-> Fe(OH)3 + 3H+
Therefore;
decreasing pH is high pH to low pH:
KClO2 > MgCl2 > FeCl2 > FeCl3
b) NH4Br, NaBrO2, NaBr, NaClO2.
NH4Br is acidic, forms NH4+ and NH4+ dnates H+ to form NH3 andH+
NaBrO2 is basic, forms Na+ + BrO2- then H2O + BrO2- HBrO2
NABr is neutral, NaClO2 is basics, forms Na+ + ClO2-then H2O + ClO2- HClO2
decreasig pH:
NaClO2 > NaBrO2 > NaBr >NH4Br
Note that HClO2 is stronger acid than HBrO2, therefore, expectmore HBrO2 formation
NaBrO2 > NaClO2 > NaBr >NH4Br
