20 ml of a 1.0 m hcl solution are added to 3.0 l of acid solution with a ph of 5.35. the ph of the mixture rises to 5.33 was the
1 answer:
You might be interested in
The question is incomplete . The complete question is :
100 mg of an unknown protein are dissolved in enough solvent to make 5.00mL of solution. The osmotic pressure of this solution is measured to be 0.107atm at 25.0°C. Calculate the molar mass of the protein. Round your answer to 3 significant digits.
Answer: The molar mass of the protein is
Explanation:
where,
= osmotic pressure of the solution = 0.107 atm
i = Van't hoff factor = 1 (for non-electrolytes)
Mass of solute (protein) = 100 mg = 0.1 g (Conversion factor: 1 g = 1000 mg)
Volume of solution = 5.00 mL
R = Gas constant =
T = temperature of the solution =
Putting values in above equation, we get:
Hence, the molar mass of the protein is