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4 years ago

Can someone explain how to do this and answer 5-8

Mathematics

2 answers:

Shkiper50 [21]4 years ago

6 0

#5 is 96 because it is congruent to the one on top

Murljashka [212]4 years ago

4 0

All angles that are being looked for happen to be the same as that stated if the question looks for reasoning it is because of alternate angles in all apart from 7 which is corresponding

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jonny [76]

Answer:I think it d

Step-by-step explanation:

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3 years ago

What is the relationship between the sine and cosine of the complementary angles in this diagram? drag and drop the answers into

Leno4ka [110]

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Step-by-step explanation:

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3 years ago

Helppp 3 out of the 5 im gunna post!

Nadusha1986 [10]

look where the line is on the y axis at x =2

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3 years ago

A tourist in Ireland wants to visit six different cities. How many different routes are possible?

hammer [34]

Answer:

$6P6 = \frac{6!}{(6-6)!}=\frac{6!}{0!}= 6! =6*5*4*3*2*1=720$

D. 720

Step-by-step explanation:

For this case we have 6 different cities that needs to be ordered in different ways. And the best way to solve this problem is using permutations since we can't repeat the route.

We need to remember the concept of permutation.

A permutation, known as "arrangement number" "is a rearrangement of the elements of an ordered list S into a one-to-one correspondence with S itself". Where S correspond to the sample space. And the formula is given by:

$nPX = \frac{n!}{(n-x)!}$

And for this case we have a total of 6 cities and we want to know how many routes with these 6 cities we can create, so then n=6 and k=6 and if we replace we got:

$6P6 = \frac{6!}{(6-6)!}=\frac{6!}{0!}= 6! =6*5*4*3*2*1=720$

And then we have 720 ways to visit six different cities. So the best option is:

D. 720

7 0

3 years ago

A college admissions officer for an MBA program has determined that historically,candidates have undergraduate grade point avera

alex41 [277]

Answer:

$2.724< \mu$

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=2.90$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=0.45$ represent the population standard deviation

n=25 represent the sample size

We have the following distribution for the random variable:

$X \sim N(\mu , \sigma=0.45)$

And by the central theorem we know that the distribution for the sample mean is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

2) Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=\pm 1.96$

Now we have everything in order to replace into formula (1):

$2.90-1.96\frac{0.45}{\sqrt{25}}=2.724$

$2.90+1.96\frac{0.45}{\sqrt{25}}=3.076$

So on this case the 95% confidence interval would be given by (2.724;3.076)

$2.724< \mu$

5 0

3 years ago