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Annette [7]
3 years ago
12

Which of the following human activities could have an irreversible effect on an ecosystem? I. introducing a new species II. urba

n sprawl III. introducing a new chemical IV. over-hunting
Chemistry
2 answers:
pav-90 [236]3 years ago
6 0
Introducimg a new chemicsl to the enviormrnt snd posssibly a new hunting techniquie 
Ulleksa [173]3 years ago
4 0

Answer: It is all of them

Explanation:I just had the question

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God, cure my stupidity.
Cloud [144]
The answer is the third one
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3 years ago
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Phosphorus pentachloride reacts with water to form hydrochloric acid and phosphoric acid. How many total moles of acid are forme
klio [65]

Answer:

0,13 moles of acid are produced

Explanation:

The reaction of the problem is:

PCl₅ + 4H₂O → 5HCl + H₃PO₄

Based on the reaction, 1 mole of PCl₅ produces 6 moles of acid (5 moles of HCl + 1 mole of H₃PO₄).

The molecular mass of PCl₅ is:

1P = 30,97g/mol + 5Cl = 5×35,45g/mol = <em>208,24 g/mol</em>

That means 4,5g of PCl₅ are:

4,5g PCl₅×(1mol / 208,24g) = 0,0216 moles of PCl₅. As 1 mole of PCl₅ produces 6 moles of acid, 0,0216 moles of PCl₅ produce:

0,0216 moles PCl₅ × (6 moles acid / mole of PCl₅) =

<em>0,13 moles of acid are produced</em>

I hope it helps!

3 0
3 years ago
Each year, the science club puts on a science show for the students in the elementary school. Luis is planning demonstrations to
Harlamova29_29 [7]

Mallebility, I got it right on the unit test.

6 0
3 years ago
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If I have 2 mol NaOH in 3 L of solution, what is the molarity of my solution?
qwelly [4]

Answer:

0.67 mole/litre

Explanation:

the molarity equall no. of moles ÷ volume of sol.

3 0
2 years ago
What is the maximum concentration of Ag⁺ that can be added to a 0.00750 M solution of Na₂CO₃ before a precipitate will form? (Ks
Firlakuza [10]

Answer:

\large \boxed{1.64\times 10^{-5}\text{ mol/L }}

Explanation:

Ag₂CO₃(s) ⇌2Ag⁺(aq) + CO₃²⁻(aq); Ksp = 8.10 × 10⁻¹²

                           2x      0.007 50 + x

K_{sp} =\text{[Ag$^{+}$]$^{2}$[CO$_{3}^{2-}$]} = (2x)^{2}\times 0.00750 = 8.10 \times 10^{-12}\\0.0300x^{2} = 8.10 \times 10^{-12}\\x^{2} = 2.70 \times 10^{-10}\\x = \sqrt{2.70 \times 10^{-10}} = \mathbf{1.64\times 10^{5}} \textbf{ mol/L}\\\text{The maximum concentration of Ag$^{+}$ is $\large \boxed{\mathbf{1.64\times 10^{-5}}\textbf{ mol/L }}$}

 

3 0
3 years ago
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