Answer:
Magnitude of impulsive force is <u>8 N.s</u>.
Explanation:
Given:
Force acting on the puck is, 
Time interval for which the force acts is, 
We are asked to find the impulsive force.
Impulsive force acting on a body is the sudden change in the momentum of the body due to the application of a large constant force for a very small interval of time.
Here, the hockey player applies a large force of 40 N for a very short interval of time. So, the impact on the puck is measured as Impulse and is represented by 'J'.
Impulse in terms of applied force and time interval is given as:
Plug in the given values and solve for 'J'. This gives,
Therefore, the magnitude of impulsive force is 8 N.s.
The current flowing in each resistor of the circuit is 4 A.
<h3>
Equivalent resistance of the series resistors</h3>
The equivalent resistance of the series circuit is calculated as follows;
6 Ω and 4 Ω are in series = 10 Ω
5 Ω and 10Ω are in series = 15 Ω
<h3>Effective resistance of the circuit</h3>
<h3>Current flowing in the circuit</h3>
V = IR
I = V/R
I = 24/6
I = 4 A
Learn more about resistors in parallel here: brainly.com/question/15121871
Answer:
The total energy stays the same but is converted from being stored as gravitational potential energy into kinetic energy of the car as it moves.
Explanation:
the law of conservation of energy states that the total energy of an isolated system remains constant, and since it is gaining speed that energy will be kinetic
Answer:
the critical flaw is subject to detection since this value of ac (16.8 mm) is greater than the 3.0 mm resolution limit.
Explanation:
This problem asks that we determine whether or not a critical flaw in a wide plate is subject to detection given the limit of the flaw detection apparatus (3.0 mm), the value of KIc (98.9 MPa m), the design stress (sy/2 in which s y = 860 MPa), and Y = 1.0.
Therefore, the critical flaw is subject to detection since this value of ac (16.8 mm) is greater than the 3.0 mm resolution limit.
