All categories

3 years ago

What is the total mass of water formed when 8 grams of hydrogen reacts completely with 64 grams of oxygen?

Chemistry

1 answer:

Kay [80]3 years ago

7 0

Answer would be 72 grams of H2O.

You might be interested in

A certain gas is found in the exhaust of automobiles and power plants. Consider a 1.53 L sample of a gas at a pressure of 5.6 x

Olegator [25]

The new volume of the gas that has an initial pressure of 5.6 x 10⁵ Pa is 5.7L. Details about volume of the gas can be found below.

<h3>How to calculate volume?</h3>

The volume of a gas can be calculated using the Boyle's law equation as follows:

P1V1 = P2V2

Where;

P1 = initial pressure
P2 = final pressure
V1 = initial volume
V2 = final volume

1.53 × 5.6 × 10⁵ = 1.5 × 10⁵ × V2

8.568 × 10⁵ = 1.5 × 10⁵V2

V2 = 8.57 × 10⁵ ÷ 1.5 × 10⁵

V2 = 5.7L

Therefore, the new volume of the gas that has an initial pressure of 5.6 x 10⁵ Pa is 5.7L.

Learn more about volume at: brainly.com/question/12357202

#SPJ1

6 0

2 years ago

An atom with atomic number of 6 would have how many protons?

aalyn [17]

Answer:

Explanation:

Any atom with the atomic number 6 is carbon and has 6 protons

4 0

4 years ago

Read 2 more answers

as 100 milliliters of 0.10 molar KOH is added to 100 milliliters of 0.10 molar HCL at 298 K, the pH of the res?A. decrease to 3B

Mila [183]

Answer:

C. increase to 7.

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

$KOH+HCl\rightarrow KCl+H_2O$

Thus, the molar relationship is 1 to 1, therefore, the moles are:

$n_{HCl}=0.1mol/L*0.1L=0.01molHCl\\n_{KOH}=0.1mol/L*0.1L=0.01molKOH\\$

Thus, since the entire hydrogen ions are neutralized, the pH C. increase to 7.

Best regards.

8 0

3 years ago

Consider a pot of water at 100 C. If it took 1,048,815 J of energy to vaporize the water and heat it to 135 C, how many grams of

jeka57 [31]

Answer:

There was 450.068g of water in the pot.

Explanation:

Latent heat of vaporisation = 2260 kJ/kg = 2260 J/g = L

Specific Heat of Steam = 2.010 kJ/kg C = 2.010 J/g = s

Let m = x g be the weight of water in the pot.

Energy required to vaporise water = mL = 2260x

Energy required to raise the temperature of water from 100 C to 135 C = msΔT = 70.35x

Total energy required = $2260x+x\times2.010\times(135-100)=2260x+70.35x=2330.35x$

$2330.35x=1048815\\x=450.068g$

Hence, there was 450.068g of water in the pot.

8 0

3 years ago

What is the percent concentration of a 250 ml solution with 0.120 g nacl?

Effectus [21]

0.048 percent is the answer

3 0

3 years ago