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White raven [17]
3 years ago
11

All of the following elements will form ions by gaining

Chemistry
1 answer:
KiRa [710]3 years ago
7 0

Answer:

Magnesium

Explanation:

When an atom loses are gain the electrons ions are formed.

There are two types of ions.

Anion

Cation

1 = Anion

It is formed when an atom gain the electrons. when atom gain electron negative charge is created on atom. For example.

X + e⁻ → X⁻

2= Cation

It is formed when an atom loses the electrons. when atom lose electron positive charge is created on atom. For example.

X → X⁺ + e⁻

There are seven valance electrons in iodine. To complete the octet it gain one electron and form anion.

Sulfur has six valance electrons it gain two electrons to complete the octet and form anion.

Phosphorus has five valance electrons it gain three electrons two complete the octet and form anion.

Magnesium has two valance electrons it loses two electron to complete the octet and form cation.

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All the particles gain more energy and move quicker and therefore they spread out causing air to expand

3 0
3 years ago
How many moles of aluminum oxide will be produced from 0.50 mol of oxygen? 4 al + 3 o2 2 al2o3?
LuckyWell [14K]
From the equation;
 4 Al + 3 O2 = 2 Al2O3
The mole ratio of Oxygen is to Aluminium hydroxide is  3:2.
Therefore; moles of Al2O3 is 
 (0.5/3 )× 2 = 0.333 moles
Therefore; The moles of aluminium oxide will be 0.333 moles
5 0
2 years ago
Read 2 more answers
Calculate for the following electrochemical cell at 25°C, Pt H2(g) (1.0 atm) H (0.010 M || Ag (0.020 M) Ag if E (H) - +0.000 V a
viva [34]

Answer : The correct option is, (b) +0.799 V

Solution :

The values of standard reduction electrode potential of the cell are:

E^0_{[H^{+}/H_2]}=+0.00V

E^0_{[Ag^{+}/Ag]}=+0.799V

From the cell representation we conclude that, the hydrogen (H) undergoes oxidation by loss of electrons and thus act as anode. Silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.

The half reaction will be:

Reaction at anode (oxidation) : H_2\rightarrow 2H^{+}+2e^-    

Reaction at cathode (reduction) : Ag^{+}+1e^-\rightarrow Ag    

The balanced cell reaction will be,  

H_2+2Ag^{+}\rightarrow 2H^{+}+2Ag

Now we have to calculate the standard electrode potential of the cell.

E^o_{cell}=E^o_{cathode}-E^o_{anode}

E^o_{cell}=E^o_{[Ag^{+}/Ag]}-E^o_{[H^{+}/H_2]}

E^o_{cell}=(+0.799V)-(+0.00V)=+0.799V

Therefore, the standard cell potential will be +0.799 V

4 0
3 years ago
It is advised that the bromobenzene solution be added slowly to the magnesium-ether solution so that it isn't present in a high
lara [203]

Answer:

Biphenyl

Explanation:

The reaction of bromo benzene with magnesium-ether solution yields a Grignard reagent.

The byproduct of this reaction is biphenyl. It is formed when two unreacted bromobenzene molecules are coupled together.

Hence, It is advised that the bromobenzene solution be added slowly to the magnesium-ether solution so that it isn't present in a high concentration, thus reducing the amount of biphenyl by-product formed.

4 0
3 years ago
CAN SOMEONE REWRITE/SHORTEN THIS FOR ME PLEASE? I'LL GIVE BRAINLIEST
Alex17521 [72]

Answer:

Here you go! 50% of your writing piece

Explanation:

Foods produced from or using GM organisms are often referred to as GM foods.

GM foods are developed and marketed because there is some advantage either to the producer or consumer of these GM foods. GM seed developers wanted their products to be accepted by producers and have concentrated on innovations that bring direct benefit to farmers and generally the food industry.

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7 0
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