The concentration of the chemist's working solution is 6.718 mol/L.
Given,
The volume of silver perchlorate solution (V₁) = 790 ml.
The volume of distilled water added to the silver perchlorate(V₂) = 290ml.
The concentration of a stock solution of silver perchlorate (C₂) = 18.3 mol/L.
We have to find the concentration of the chemist's working solution (C₁).
As we know,
V₁C₁ = V₂C₂
From the above formula, we get,
C₁ = V₂C₂/V₁
C₁ = 290 × 18.3/ 790
C₁ = 6.718 mol/L
The concentration of the working solution = 6.718 mol/L
Hence, the concentration of the chemist's working solution is 6.718 mol/L.
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A). Object A, because the shorter the distance between objects result in a stronger gravitational force
Answer:
its 0.163 g
Explanation:
From the total pressure and the vapour pressure of water we can calculate the partial pressure of O2
PO 2 =P t −P H 2 O
= 760 − 22.4
= 737.6 mmHg
From the ideal gas equation we write.
W= RT/PVM = (0.0821Latm/Kmol)(273+24)K(0.974atm)(0.128L)(32.0g/mol/) =0.163g
The volume is 2.23 liters of hydrogen gas.
<u>Explanation</u>:
moles of C = grams / molecular mass of C
= 1.04 g / 12.011 g/mol.
= 0.086
The ratio between C and H2 is 1 : 1
moles H2 = 0.086
V = nRT / p
= 0.086 x 0.08206 x 316 K / 1.0 atm
V = 2.23 L.
Lol i need to answer more and plus n could also = # 4.65