Answer:
Option (C) 4.5 liters
Explanation:
1mole of a gas occupy 22.4L at stp.
This implies that 1mole of He also occupy 22.4L at stp.
From the question given, we were asked to find the volume occupied by 0.20 mole of He at STP. This can be achieved by doing the following:
1mole of He occupied 22.4L.
Therefore, 0.2mol of He will occupy = 0.2 x 22.4L = 4.48 = 4.5L
3.456 x 10^2 is the answer you're looking for.
Answer: The workdone W = 505J
Explanation:
Applying the pressure-volume relationship
W= - PΔV
Where negative sign indicates the power is being delivered to the surrounding
W = - 1.0atm * ( 5.88 - 0.9)L
= - 1.0atm * (4.98)
W = -4.98 atmL
Converting to Joules
1atmL = 101.325J
-4.98atmL = x joules.
Work done in J = -4.98 * 101.325
W= -505J
Therefore the workdone is -505J
Answer:
2.82 * 10^-25 g
Explanation:
Given that :
Atomic number = 17
Mass of an atom of the element =?
Avogadro's constant = 6.022 * 10^23
The mass of an atom. Of the element is :
Atomic mass / Avogadro's constant
= 17 / 6.022 * 10^23
= 2.82 * 10^-25
=
Answer:
For these types of questions the equation that we must take into account is that:
T = PxV (where T is the temperature, P is the pressure and V is the volume) this equation is described as we consider that this is the value N and R is 1, therefore it is not necessary to explain them now.
Explanation:
The quoted equation refers to Boyle's Law, in this law we can explain that the volume increases if the pressure decreases and if the temperature also increases, if the pressure increases and the volume decreases this means that the gas is compressing assuming that the temperature is constant
