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2 years ago

How many kilojoules are released when 12.0 g of propane, C3H8, reacts?

Chemistry

1 answer:

NeTakaya2 years ago

4 0

Answer:

9/11 happened on the 11th of September

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imine formation is an acid-catalyzed process, however the procedure performed in this does not require the addition of an extern

SVETLANKA909090 [29]

Answer:

See explaination

Explanation:

Reaction between p- toluidine and o- vaniline to form imine.This reaction does occur in the presence of a acidic source.

Here the -OH group in the o- vaniline is quite acidic so it acts a internal acidic catalyst. Hence the reaction occurred in the absence of any external acidic source.The reaction mechanism is given at the attached file.

please kindly see attachment.

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3 years ago

What is the difference between accuracy and precision in chemistry ?

earnstyle [38]

Accuracy is more of a range

6 0

4 years ago

Which is a way that the elements are groupef on the periodic table

hammer [34]

Your answer is B because elements within the same column have equal numbers of valence electrons which determines the reactivity of an element.

8 0

3 years ago

4. Magnesium and oxygen undergo a chemical reaction to

erastovalidia [21]

Answer:

About 16.1 grams of oxygen gas.

Explanation:

The reaction between magnesium and oxygen can be described by the equation:
$\displaystyle 2\text{Mg} + \text{O$_2$} \longrightarrow 2\text{MgO}$

24.4 grams of Mg reacted with O₂ to produce 40.5 grams of MgO. We want to determine the mass of O₂ in the chemical change.

Compute using stoichiometry. From the equation, we know that two moles of MgO is produced from every one mole of O₂. Therefore, we can:

Convert grams of MgO to moles of MgO.
Moles of MgO to moles of O₂
And moles of O₂ to grams of O₂.

The molecular weights of MgO and O₂ are 40.31 g/mol and 32.00 g/mol, respectively.

Dimensional analysis:

$\displaystyle 40.5\text{ g MgO} \cdot \frac{1\text{ mol MgO}}{40.31\text{ g MgO}} \cdot \frac{1\text{ mol O$_2$}}{2\text{ mol MgO}} \cdot \frac{32.00\text{ g O$_2$}}{1\text{ mol O$_2$}} = 16.1\text{ g O$_2$}$

In conclusion, about 16.1 grams of oxygen gas was reacted.

You will obtain the same result if you compute with the 24.4 grams of Mg instead:

$\displaystyle 24.4\text{ g Mg}\cdot \frac{1\text{ mol Mg}}{24.31\text{ g Mg}} \cdot \frac{1\text{ mol O$_2$}}{1\text{ mol Mg}} \cdot \frac{32.00\text{ g O$_2$}}{1\text{ mol O$_2$}} = 16.1\text{ g O$_2$}$

3 0

2 years ago

If a sound wave speeds up and its frequency does not change, what happens to the wavelength?

yan [13]

Answer: No, the speed of propagation is constant in a given medium; only the wavelength changes as the frequency changes.

Explanation:

5 0

2 years ago