The desired formula parameters for Newton's Law of Cooling can be found from the given data. Then the completed formula can be used to find the temperature at the specified time.

<h3>Given:</h3>

$T(t)=T_a+(T_0-T_a)e^{-kt}\\\\T_a=68,\ T_0=208,\ (t,T)=(3,185)$

T(4)

<h3>Solution:</h3>

Filling in the given numbers, we have ...

185 = 68 +(208 -68)e^(-k·3)

117/140 = e^(-3k) . . . . . subtract 68, divide by 140

ln(117/140) = -3k . . . . . . take natural logarithms

k = ln(117/140)/-3 ≈ 0.060

The temperature after 4 minutes is about ...

T(4) = 68 +140e^(-0.060·4) ≈ 68 +140·0.787186

T(4) ≈ 178.205

After 4 minutes, the final temperature is about 178 °F.

3 0

3 years ago

Martene got a small aquarium for her birthday. the aquarium is a right rectangular prism 18.5cm long by 15cm wide. martene put 3

shusha [124]

3885 = 18.5 * 15 * height
The water is 14cm deep in the aquarium.

7 0

3 years ago

Read 2 more answers

Help me with this it's confusing :(

fredd [130]

For the equation it would be y=my+b

3 0

3 years ago

You and your friend are standing back-to-back. Your friend runs 14 feet forward and then 7 feet right. At the same time, you run

garri49 [273]

Answer:

30.52 feet.

Step-by-step explanation:

3 0

3 years ago