Answer:
a = 50 [m/s²]
Explanation:
This type of problem can be solved using Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
∑F = m*a
where:
F = force =25 [N] (units of Newtons)
m = mass = 0.5 [kg]
a = acceleration [m/s²]
The kind of vegetation that alfisols support is a temperate forest. Alfisols develop under the temperate broadleaf deciduous forests. Broadleaf trees tend to be nutrient demanding, and their leaves are filled with major nutrient elements. The litter from this type of forest is not the acidic type, either.
Answer:
The speed of the man is 4.54 m/s.
Explanation:
Given that,
Mass of man=8100 g
Mass of stone = 79 g
Speed = 4.5 m/s
We need to calculate the speed of the man
Using momentum of conservation
Where,
=mass of man
=mass of stone
=velocity of man
=velocity of stone
Put the value in the equation
As the stone is away from the man
So, the speed of stone is zero
Hence, The speed of the man is 4.54 m/s.
Answer:
Δx=vt−21at2
Explanation:
We can figure out which kinematic formula to use by choosing the formula that includes the known variables, plus the target unknown.
In this problem, the target unknown is the acceleration as the cyclist slows down.
Assuming the initial direction of travel is the positive direction, our known variables are
t=0.5s
v=10km/h
Δx=2m
Since we don't know the initial velocity (Vo), and we are not asked to find (Vo) we could use the kinematic formula that is missing (Vo) to solve for the target unknown, A
Δx=vt−21at