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3 years ago

Please help me 5. Where is potential energy decreasing? А B C D

Chemistry

2 answers:

Nataly [62]3 years ago

7 0

Answer:

Explanation:

I believe it is D. your kinetic energy would be at b. A, the cart would be going at a constant rate, because there is no hill or steep slope.

zepelin [54]3 years ago

4 0

B it is goin down hill and that means it decreased

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Match these items.

mars1129 [50]

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3. CnH2n - E. general formula for alkenes
4. reaction typical of unsaturated hydrocarbons - A. addition
5. CnH2n-2 - F. general formula for alkynes
6. series name of hydrocarbons with triple bond - D. alkyne
7. CnH2n+2 - B. general formula of alkanes

6 0

3 years ago

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What is the term for the number of protons in the nucleus of each atom of an element?

xxTIMURxx [149]

Answer:

atomic number

Explanation:

atomic number is the number of protons

5 0

2 years ago

Please help me thanks

Digiron [165]

Answer:

your finger becomes negatively charged

Explanation:

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3 years ago

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A 7.0 g sample of a hydrocarbon (a molecule that has only hydrogen and carbon) is subject to combustion analysis. The mass of CO

Akimi4 [234]

Answer: The empirical formula for the given compound is $CH_2$

Explanation:

The chemical equation for the combustion of compound having carbon and hydrogen follows:

$C_xH_y+O_2\rightarrow CO_2+H_2O$

where, 'x' and 'y' are the subscripts of carbon and hydrogen respectively.

We are given:

Mass of $CO_2=22.0g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 22.0 g of carbon dioxide, $\frac{12}{44}\times 22.0=6g$ of carbon will be contained.

For calculating the mass of hydrogen:

Mass of hydrogen = Mass of sample - Mass of carbon

Mass of hydrogen = 7.0 g - 6 g

Mass of hydrogen = 1.0 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{6g}{12g/mole}=0.5moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{1.0g}{1g/mole}=1.0moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.5 moles.

For Carbon = $\frac{0.5}{0.5}=1$

For Hydrogen = $\frac{1.0}{0.5}=2$

Step 3: Taking the mole ratio as their subscripts.

The ratio of Fe : C : H = 1 : 2

Hence, the empirical formula for the given compound is $C_{1}H_{2}=CH_2$

4 0

3 years ago

In air, a silver object can tarnish due to the reaction of silver with hydrogen sulfide, a gas found in the air as a result of c

cluponka [151]

Answer:

The coefficient of Ag is 2.

Explanation:

___Ag (s) + ___H₂S (g) ⇒ ___ Ag₂S (s) + ___ H₂(g)

The Law of Conservation of Matter is also called the law of conservation of mass or the Law of Lomonósov-Lavoisier. This law postulates that "the mass is not created or destroyed, only transformed." This means that the reagents interact with each other and form new products with physical and chemical properties different from those of the reagents because the atoms of the substances are ordered differently. But the amount of matter or mass before and after a transformation (chemical reaction) is always the same, that is, the quantities of the masses involved in a given reaction must be constant at all times, not changing in their proportions when the reaction ends.

In others words, the law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

Then, you must balance the chemical equation. For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts :

Left side: 1 Ag, 2 H and 1 S

Right side: 2 Ag, 2 H and 1 S

The coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.

By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.

You can see that the elements H and S are balanced because we have the same quantity on both sides of the reaction. Then you must balance the Ag, so the reaction is:

2 Ag (s) + 1 H₂S (g) ⇒ 1 Ag₂S (s) + 1 H₂(g)

Now you have:

Left side: 2 Ag, 2 H and 1 S

Right side: 2 Ag, 2 H and 1 S

So, you have the same amount of each element to both of the reaction and this is balanced.

Then, the coefficient of Ag is 2.

7 0

3 years ago