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shutvik [7]
3 years ago
11

Please help me 5. Where is potential energy decreasing? А B C D

Chemistry
2 answers:
Nataly [62]3 years ago
7 0

Answer:

D

Explanation:

I believe it is D. your kinetic energy would be at b. A, the cart would be going at a constant rate, because there is no hill or steep slope.

zepelin [54]3 years ago
4 0
B it is goin down hill and that means it decreased
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What is the pOH of a solution of HNO3 that has [OH– ] = 9.50 × 10–9 M?
Arturiano [62]
The correct answer to that question is
= 8.02
7 0
3 years ago
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  complete and balance the following reactions ?   uo2+ +cr o^2- 7 ـــــــــــــــــــــ uo2+ +cr3+
ivanzaharov [21]
In order to <span>complete and balance the following reactions, you should add a Fe into it. So it will look like  uo2+ +cr o^2- 7 ـــــــــــــــــــــ uo2+ +cr3+Fe. The answer to the following given statement or missing answer is Fe. </span>
3 0
4 years ago
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A/1 * B/C = D
Anit [1.1K]

Answer: 0.64 Moles of Propane

Explanation:

Data:

        Moles of Carbon  =  1.5 mol

        Conversion factor  =  7 mol C produces = 3 mol of Propane

Solution:

            As we know,

               7 moles of Carbon produces =  3 moles of Propane

Then,

           1.5 moles of Carbon will produce  =  X moles of Propane

Solving for X,

                    X =  (1.5 moles × 3 moles) ÷ 7 moles

                    X  =  0.6428571 moles of Propane

Or rounded to two significant figures,

                    X =  0.64 Moles of Propane

Read more on Brainly.com - brainly.com/question/11464115#readmore

3 0
3 years ago
How many moles of lithium are present in a sample that contains 2.45x10^87 formula units of Li2SO4?​
ddd [48]

The answer is: 8.14·10⁶³ moles of lithium are present.

N(Li₂SO₄) = 2.45·10⁸⁷; number of formula units of lithium sulfate.

n(Li₂SO₄) = N(Li₂SO₄) ÷ Na.

n(Li₂SO₄) = 2.45·10⁸⁷ ÷ 6.022·10²³ 1/mol.

n(Li₂SO₄) = 4.07·10⁶³ mol; amount of lithium sulfate

In one molecule of lithium sulfate, there are two atoms of lithium.

n(Li₂SO₄) : n(Li) = 1 : 2.

n(Li) = 2 · 4.07·10⁶³ mol.

n(Li) = 8.14·10⁶³ mol; amount of lithium atoms.

3 0
3 years ago
16. Mass = 10g
inessss [21]

Actual volume=Final Volume-initial volume

\\ \sf\longmapsto 50ml-30ml=20ml

Now

\\ \sf\longmapsto Density=\dfrac{Mass}{Volume}

\\ \sf\longmapsto Density=\dfrac{10}{20}

\\ \sf\longmapsto Density=2g/ml

3 0
3 years ago
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