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3 years ago

Please help me 5. Where is potential energy decreasing? А B C D

Chemistry

2 answers:

Nataly [62]3 years ago

7 0

Answer:

Explanation:

I believe it is D. your kinetic energy would be at b. A, the cart would be going at a constant rate, because there is no hill or steep slope.

zepelin [54]3 years ago

4 0

B it is goin down hill and that means it decreased

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Which action is a critical part of listening?

jenyasd209 [6]

Option A

using verbal and nonverbal communication to show a person is listening is a critical part of listening

<u>Explanation:</u>

An adequate hearer obligation listens and recognizes the language sounds focused approaching them, know the information of the sounds, critically estimate or estimate that information, retrieve what’s implied stated, and acknowledge either orally or nonverbally to erudition they’ve earned.

Answering occasions imparting literal and nonverbal intelligence that show attentiveness and perception or a shortage thereof. We convey verbatim and nonverbal feedback while the added character is speaking and later they are ingested. Assess the trustworthiness, completeness, and quality of an information ere responding with lexical and nonverbal beacons.

6 0

3 years ago

The enthalpy of combustion of hard coal averages -35 kJ/g, that of gasoline, 1.28 x 105 kJ/gal. How many kilograms of hard coal

Ganezh [65]

Answer:

3.657 kg

Explanation:

Given:

Enthalpy of combustion of hard coal = -35 kJ/g

Enthalpy of combustion of gasoline = 1.28 × 10⁵ kJ/gal

Density of gasoline = 0.692 g/mL

now,

The heat provide 1 gallon of gasoline provide = 1.28 × 10⁵ kJ

and,

heat provided by the 1 gram of coal = 35 kJ

1 kJ of heat is provided by (1/35) gram of hard coal

therefore,

For 1.28 × 10⁵ kJ of heat, mass of hard coal = 1.28 × 10⁵ kJ × (1 / 35)

For 1.28 × 10⁵ kJ of heat, mass of hard coal = 3657.14 grams = 3.657 kg

3 0

3 years ago

A gas occupies a volume of 140 mL at 35.0°C and 697 mm Hg. What is the volume of the gas at STP?

Harlamova29_29 [7]

Answer:

113.80 mL

Explanation:

Given that:

Volume $V_1 = 140 mL$

Temperature $T_1 = 35.0^0C$

$= (273 + 35) = 308 \ K$

Pressure $P_1 = 697 mmHg$

At standard temperature and pressure;

Temperature $T_2 = 273 K$

Pressure $P_2$ = 760 mmHg

Using the formula for a combined gas law:

$\dfrac{P_1V_1}{T_1} = \dfrac{P_2V_2}{T_2}$

$V_2 = \dfrac{P_1V_1T_2}{T_1P_2}$

$V_2 = \dfrac{697 \ mmHg \times 140 \ mL \times 273 \ K }{308 \ K \times 760 \ mmHg}$

$\mathbf{V_2 = 113.80 \ mL}$

6 0

3 years ago

Calculate the frequency of the light emitted by ahydrogen atom

lesya [120]

Answer: $0.31\times 10^{16}Hz$ .

Explanation:

$E=\frac{hc}{\lambda}$

$\lambda$ = Wavelength of radiation

E= energy

Using Rydberg's Equation:

$\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )\times Z^2$

Where,

$\lambda$ = Wavelength of radiation = ?

$R_H$ = Rydberg's Constant

$n_f$ = Higher energy level = 4

$n_i$ = Lower energy level = 1

Z= atomic number = 1 (for hydrogen)

Putting the values, in above equation, we get

$\frac{1}{\lambda}=10973731.6m^{-1}\left(\frac{1}{1^2}-\frac{1}{4^2} \right )\times 1$

$\lambda=9.7\times 10^{-8}m$

The relationship between wavelength and frequency of the wave follows the equation:

$\nu=\frac{c}{\lambda}$

where,

$\nu$ = frequency of the wave = ?

c = speed of light = $3\times 10^8ms^{-1}$

$\lambda$ = wavelength of the wave = $9.7\times 10^{-8}m$

$\nu=\frac{3\times 10^8ms^{-1}}{9.7\times 10^{-8}m}$

$\nu=0.31\times 10^{16}s^{-1}=0.31\times 10^{16}Hz$

The frequency of the light emitted by a hydrogen atom during a transition of its electron from the n = 4 to the n = 1 principal energy level is $0.31\times 10^{16}Hz$ .

5 0

3 years ago

I need help please and give me an explanation

jeyben [28]

Column 1 because it has 1/8 valence electrons and alkaline metals are reactive

5 0

3 years ago