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Serhud [2]
4 years ago
14

PLEASE HELP ASAP. Best answer gets BRAINIEST:

Physics
1 answer:
nikklg [1K]4 years ago
3 0

Answer:

1. Force = -623.43 N

2.Tension = 106.65 N

Explanation:

Let us call the bigger mass M, and the smaller mass m.

Since the two masses are connected to each other, they must experience same acceleration (if they didn't, the unequal acceleration will cause the string to break. )

From the free body diagram, the forces acting on the mass M are

T - Mg-F_p,

and according to Newton Second Law, this causes acceleration a; therefore,

(1).  \boxed{ T-Mg-F_p=Ma}.

Similarly, the forces acting on the mass m are

T -mg,

which causes the acceleration -a (upward); therefore,

T-mg=-ma \\

or

\boxed{ mg-T = ma}

From this equation we solve for T and get:

T = mg-ma \\\\T =m(g-a).

We put this into equation (1) and get:

m(g-a)-Mg-F_p=Ma

F_p = m(g-a)-M(g+a)

putting in M=62.4kg,m=13.5kg, and a=1.9m/s^2, we get:

F_p=13.5(9.8-1.9)-62.4(9.8+1.9)\\\\\boxed{ F_p=-623.43N}

The tension in the wire is

T =m(g-a)\\\\T = 13.5(9.8-1.9)\\\\\boxed{ T= 106.65N}

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A stone is thrown straight up. when it reaches it’s highest point, _____
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both it velocity and acceleration is zero.

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3 years ago
Is it proper to use an infinitely long cylinder model when finding the temperatures near the bottom or top surfaces of a cylinde
Gelneren [198K]

Answer:

No, it is not proper to use an infinitely long cylinder model when finding the temperatures near the bottom or top surfaces of a cylinder.

Explanation:

A cylinder is said to be infinitely long when is of a sufficient length. Also, when the diameter of the cylinder is relatively small compared to the length, it is called infinitely long cylinder.

Cylindrical rods can also be treated as infinitely long when dealing with heat transfers at locations far from the top or bottom surfaces. However, it not proper to treat the cylinder as being infinitely long when:

* When the diameter and length are comparable (i.e have the same measurement)

When finding the temperatures near the bottom or top of a cylinder, it is NOT PROPER TO USE AN INFINITELY LONG CYLINDER because heat transfer at those locations can be two-dimensional.

Therefore, the answer to the question is NO, since it is not proper to use an infinitely long cylinder when finding temperatures near the bottom or top of a cylinder.

8 0
3 years ago
A magnetic force can act on an electron even when it A) is at rest B) moves parallel to magnetic field lines C) both of these D)
Kobotan [32]

Answer: A)

Explanation: when an electron is placed in a magnetic field, it experiences a force.

This force is given below as

F=qvB*sinθ

F = force experienced by charge.

q = magnitude of electronic charge

v = speed of electron

B= strength of magnetic field

θ = angle between magnetic field and velocity.

What defines the force exerted on the charge is the angle between the field and it velocity.

If magnetic field is parallel to velocity, then it means that θ=0° which means sin 0 = 0, which means

F = qvB * 0 = 0.

The charge being at rest has nothing to do with the angle between magnetic field strength and velocity.

3 0
4 years ago
A 10 kg ball is held above a building with a height of 30 m. What is the
Darina [25.2K]

Answer: 2940 J

Explanation: solution attached:

PE= mgh

Substitute the values:

PE= 10kg x 9.8 m/s² x 30 m

= 2940 J

6 0
4 years ago
A centrifuge in a medical research laboratory rotates at an angular speed of 3,650 rev/min. When switched off, it rotates 46.0 t
erma4kov [3.2K]

Answer:

The constant angular acceleration of the centrifuge = -252.84 rad/s²

Explanation:

We will be using the equations of motion for this calculation.

Although, the parameters of this equation of motion will be composed of the angular form of the normal parameters.

First of, we write the given parameters.

w₀ = initial angular velocity = 2πf₀

f₀ = 3650 rev/min = (3650/60) rev/s = 60.83 rev/s

w₀ = 2πf₀ = 2π × 60.83 = 382.38 rad/s

θ = 46 revs = 46 × 2π = 289.14 rad

w = final angular velocity = 0 rad/s (since the centrifuge come rest at the end)

α = ?

Just like v² = u² + 2ay

w² = w₀² + 2αθ

0 = 382.38² + [2α × (289.14)]

578.29α = -146,214.4644

α = (-146,214.4644/578.29)

α = - 252.84 rad/s²

Hope this Helps!!!

6 0
4 years ago
Read 2 more answers
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