The dancing bear family loves when their trainer gives them little treats to reward them for a good performance. If the trainer
1 answer:
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Answer:
The pitching speed of your friend is 33.20 m/s
Explanation:
<em>Lets explain how to solve the problem</em>
Your friend throw the ball horizontally that means the vertical initial
component of velocity is zero ().
The ball is thrown from a height 4 meters above the ground.
The height
<u><em>Remember:</em></u> the height is negative value because its below the point of
thrown (initial position)
h = -4 m , and g = -9.8 m/s²(downward)
<em>Substitute these values in the rule above</em>
⇒
⇒ -4 = -4.9t² (multiply both sides by -1)
⇒ 4 = 4.9t² (divide both sides by 4.9)
⇒ 0.81633 = t² (take √ for both sides)
⇒ <em>t = 0.9035</em>
Then the time of the ball to land on the ground is 0.9035 seconds
The range of the ball on the ground is 30 m
The range , where
is the horizontal
component of the initial velocity
R = 30 meters and t = 0.9035
⇒ (divide both sides by 0.9035)
⇒ m/s
<em>The pitching speed of your friend is 33.20 m/s </em>
Answer:
Tension T1 is less than tension T2.
T1 < T2
Explanation:
According to given data,
mass of box A ( mA) is grater than mass of box B (mB)
we can write,
m(A) > m(B)
Newton's second law states that:
Tension of object is directly proportional to the mass of the system.
T ∝ m
here Boxes A and B are being pulled to the right on a frictionless surface,
so Tension T1 generates due to the mass of box A m(A)
and Tension T2 arises due to mass of the system m(A) + m(B)
Thus tension T1 will be less than tension T2
T1 < T2
learn more about Tension force here:
<u>brainly.com/question/13175014</u>
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A bowling ball of 7.0 kg will be weighed around 15.54 lbs (pounds) at the surface of the Earth.
<u>Explanation:</u>
The weight of the bowling ball as given in the question,
Since we know that the force of gravity acting on an object at the surface of the Earth is 2.22 lb i.e. the object will be weighed as 2.22 lb at the surface of the Earth. Similarly, here in this case;
The weight of the bowling ball,
Hence, the bowling ball will be weighed as 15.54 lbs at the surface of the Earth.