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Lelu [443]
3 years ago
8

What is the molarity of 70.6 g C2H6O in 2.25 L of solution

Chemistry
1 answer:
myrzilka [38]3 years ago
7 0

Hey there!

Molar mass C2H6O = 46.0684 g/mol

Number of moles:

n = mass of solute / molar mass

n = 70.6 / 46.0684

n = 1.532 moles

Therefore:

M = number of moles / volume ( L )

M = 1.532 / 2.25

= 0.680 M

Hope that helps!

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SI units are based on multiples of what number?
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SI unites are based on multiplying or dividing by 10, 100, 1,000, 10,000 (and so on...) depending on the unit you're solving for.
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3 years ago
HELP PLSSSSS!!
11Alexandr11 [23.1K]

Answer:

68133080.02 g

Explanation:

I believe that the question is to find the mass of air in the room and not the molar mass of air since the molar mass of air was already given in the question as 28.97 g/mol.

Now, if 1 mole of a gas occupies 22.4 L

x moles of air occupies 52,681,428.8 Liters

x = 1 * 52,681,428.8 /22.4

x = 2351849.5 moles of air

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3 years ago
Homogeneous mixtures
galina1969 [7]

Explanation:

<h3>The mixture in which the particles of the components of solute and solvent are equally mixed is called homogeneous mixture. </h3>
8 0
3 years ago
Read 2 more answers
True or False? Not all compounds will dissolve in water.
In-s [12.5K]

Answer:

False

Explanation:

Polar molecules and ionic compounds dissolve in water, not nonpolar molecules

4 0
3 years ago
What is the mass of a piece of iron that releases 179.85 joules of heat as it cools from 51.29 degrees Celsius to 31.42 degrees
Sedaia [141]

Answer:

20.11 g.

Explanation:

What is given?

c (specific heat of iron) = 0.450 J/g °C.

Q (heat energy) = 179.85 J.

ΔT (change of temperature) = |31.42 °C - 51.29 °C| = 19.87 °C.

What do we need? Mass of iron (m)

Step-by-step solution:

Let's see the formula of specific heat:

c=\frac{Q}{m\cdot\Delta T}

Where c is specific heat, Q is heat energy, m is mass and ΔT is the change of temperature.

We just have to solve for 'm' to find the mass of iron and replace the given data that we have, like this:

m=\frac{Q}{c\cdot\Delta T}=\frac{179.85\text{ J}}{0.450\text{ }\frac{J}{g\cdot\degree C}\cdot19.87\degree C}=20.11\text{ g.}

The mass of the iron would be 20.11 g.

5 0
1 year ago
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