Both theoretical and actual yields would be needed to calculate percent yield.
The percent yield of a reaction is defined as the ratio of the actual yield to that of the theoretical yield. It can be mathematically expressed as:
percent yield = actual yield/theoretical yield x 100%
The actual yield is the amount of a specific product produced from a reaction while the theoretical yield is the stoichiometric amount of the same product.
More on percent yield can be found here: brainly.com/question/2506978?referrer=searchResults
Heterogeneous mixture. cause you can separate the noodles from soup
Answer:
V₂ = 16.5 L
Explanation:
To solve this problem we use <em>Avogadro's law, </em>which applies when temperature and pressure remain constant:
V₁/n₁ = V₂/n₂
In this case, V₁ is 22.0 L, n₁ is [mol CO + mol NO], V₂ is our unknown, and n₂ is [mol CO₂ + mol N₂].
- n₁ = mol CO + mol NO = 0.1900 + 0.1900 = 0.3800 mol
<em>We use the reaction to calculate n₂</em>:
2CO(g) + 2NO(g) → 2CO₂(g) + N₂(g)
0.1900 mol CO * 
0.1900 mol CO₂
0.1900 mol NO * 
0.095 mol N₂
- n₂ = mol CO₂ + mol N₂ = 0.1900 + 0.095 = 0.2850 mol
Calculating V₂:
22.0 L / 0.3800 mol = V₂ / 0.2850 mol
V₂ = 16.5 L
Answer:
545.2
Explanation:
To read a beam balance, you need to add together the numbers that each balance reads.
The first beam reads 500.
The second beam reads 40.
The third beam reads 5.2.
500 + 40 + 5.2 = 545.2
The total mass of the rock sample is 545.2.
Answer:
mass of CO₂ = 5.402 g
Explanation:
At STP, 1 mole of any gas takes up 22.4L of volume
Thus, 1 mole = 22.4 L
1 L = 1 mole ÷ 22.4
Therefore, 2.75 L = 2.75 mole ÷ 22.4 = 0.123 moles
Molecular weight of CO₂ = 44 g/mole
mass of CO₂ = molecular weight * number of moles = 44 g/mole * 0.123 moles
mass of CO₂ = 5.402 g
