Answer:
1st value = 1.828 * 10 ^9 gm/m^2 ------- 10th value = 7.312 * 10^9 gm/m^2
Explanation:
initial load ( Wp) = 200 g
W1 ( value by which load values increase ) = 100 g
Ten different beam loading values :
Wp + w1 = 300g ----- p1
Wp + 2W1 = 400g ---- p2
Wp + 3W1 = 500g ----- p3 ----------------- Wp + 10W1 = 1200g ---- p10
x = 10.25" = 0.26 m
b = 1.0" = 0.0254 m
t = 0.125" = 3.175 * 10^-3 m
using the following value to determine the load values at different beam loading values
attached below is the remaining part fo the solution
Answer:
to make the bace of a building more sturdy
Explanation:
example: the bace of the empire state building is stone very sturdy
Answer:
The displacement from t = 0 to t = 10 s, is -880 m
Distance is 912 m
Explanation:
. . . . . . . . . . A
integrate above equation we get

from information given in the question we have
t = 1 s, s = -10 m
so distance s will be
-10 = 12 - 1 + C,
C = -21

we know that acceleration is given as
[FROM EQUATION A]
Acceleration at t = 4 s, a(4) = -24 m/s^2
for the displacement from t = 0 to t = 10 s,

the distance the particle travels during this time period:
let v = 0,

t = 2 s
Distance ![= [s(2) - s(0)] + [s(2) - s(10)] = [1\times 2 - 2^3] + [(12\times 2 - 2^3) - (12\times 10 - 10^3)] = 912 m](https://tex.z-dn.net/?f=%3D%20%5Bs%282%29%20-%20s%280%29%5D%20%2B%20%5Bs%282%29%20-%20s%2810%29%5D%20%3D%20%5B1%5Ctimes%202%20-%202%5E3%5D%20%2B%20%5B%2812%5Ctimes%202%20-%202%5E3%29%20-%20%2812%5Ctimes%2010%20-%2010%5E3%29%5D%20%3D%20912%20m)