Answer:
8.85 Ω
Explanation:
Resistance of a wire is:
R = ρL/A
where ρ is resistivity of the material,
L is the length of the wire,
and A is the cross sectional area.
For a round wire, A = πr² = ¼πd².
For aluminum, ρ is 2.65×10⁻⁸ Ωm, or 8.69×10⁻⁸ Ωft.
Given L = 500 ft and d = 0.03 in = 0.0025 ft:
R = (8.69×10⁻⁸ Ωft) (500 ft) / (¼π (0.0025 ft)²)
R = 8.85 Ω
Answer:
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Explanation:
Based on the information, both technician A and technician B are correct.
<h3>How to depict the information?</h3>
From the information given, Technician A says that mechanical shifting controls can wear out over time.
Technician B says that vacuum control rubber diaphragms can deteriorate over time.
In this case, both technicians are correct as the information depicted is true.
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