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motikmotik
2 years ago
14

For which of the following reactions is the ratio kp/kc largest at 300 k?

Chemistry
2 answers:
Yanka [14]2 years ago
8 0

Answer:

Reaction c. has the largest value of \frac{k_{p} }{k_{c} } =  1.55 X 10^{10} at 300 K

Explanation:

Here is the complete question

Converting between Kc and Kp For which of the following reactions is the ratio Kp/Kc largest at 300 K?  

a. N2(g) + O2(g) ⇌ 2 NO(g)

b. C(s) +2H2(g) ⇌ CH4(g)

c. Ni(CO)4(g) ⇌ Ni(s) + 4CO(g)

d. CaCO3(s) ⇌ CaO(s) + CO2(g)

Solution

k_{p} = k_{c}(RT)^{n}\\\frac{k_{p} }{k_{c} } =  (RT)^{n}

where R = molar gas constant = 8.314 J/mol-K, T = temperature = 300 K and n = number of moles of products - number of moles of reactants

For reaction a. number of moles of gaseous products = 2, number of moles of gaseous reactants = 2. So n = 2 - 2 = 0

So, \frac{k_{p} }{k_{c} } =  (RT)^{n} = (RT)^{0} = 1

For reaction b. number of moles of gaseous products = 1, number of moles of gaseous reactants = 2. So n = 1 - 2 = -1 (we do not include the solid)

So, \frac{k_{p} }{k_{c} } =  (RT)^{n} = (RT)^{-1} = (8.314 X 300)^{-1} = (2494.2)^{-1} = 4.01   X 10^{-4}

For reaction c. number of moles of gaseous products = 5, number of moles of gaseous reactants = 1. So n = 4 - 1 = 3 (we do not include the solid)

So, \frac{k_{p} }{k_{c} } =  (RT)^{n} = (RT)^{3} = (8.314 X 300)^{3} = (2494.2)^{3} = 1.55 X 10^{10}

For reaction d. number of moles of gaseous products = 2, number of moles of gaseous reactants = 0. So n = 2 - 0 = 2 (we do not include the solid)

So, \frac{k_{p} }{k_{c} } =  (RT)^{n} = (RT)^{2} = (8.314 X 300)^{2} = (2494.2)^{2} = 6.22 X 10^{6}

Since \frac{k_{p} }{k_{c} } =  1.55 X 10^{10} for reaction c which is the largest value. So, reaction c. has the largest value of \frac{k_{p} }{k_{c} } =  1.55 X 10^{10} at 300 K

Novosadov [1.4K]2 years ago
3 0
Below are the choices:

<span>A. Ni(CO)4(g) ⇌ Ni(s) + 4CO(g)
B. C(s) +2H2(g) ⇌ CH4(g)
C. CaCO3(s) ⇌ CaO(s) + CO2(g)
D. N2(g) + O2(g) ⇌ 2 NO(g)
</span>
The answer is A. Ni(CO)4(g) ⇌ Ni(s) + 4CO(g)

<span>The Kp/Kc ratio is equal to (RT)Δn. K is a constant and the temperature is held constant. So, the Kp/Kc ratio depends on Δn or the difference of moles of gaseous product and reactant. The reaction with the greatest Kp/Kc ratio is Ni(CO)4(g) ⇌ Ni(s) + 4CO(g) with a Δn of 3.</span>
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1.66 moles.

Explanation:

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Next, we shall determine the number of mole in 23.2 g of Hydrogen gas, H2.

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Molar mass of H2 = 2x1 = 2 g/mol

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Next, the balanced equation for the reaction. This is given below:

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From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2 to produce 2 moles of NH3.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2.

Therefore, 0.83 moles will react with = (0.83 x 3) = 2.49 moles of H2.

From the calculations made above, we can see that only 2.49 moles out of 11.6 moles of H2 is required to react completely with 0.83 mole of N2.

Therefore, N2 is the limiting reactant.

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From the balanced equation above,

1 mole of N2 reacted to produce 2 moles of NH3.

Therefore, 0.83 mole of N2 will react to produce = (0.83 x 2) = 1.66 moles of NH3.

Therefore, the maximum amount of NH3 produced from the reaction is 1.66 moles.

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