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motikmotik
3 years ago
14

For which of the following reactions is the ratio kp/kc largest at 300 k?

Chemistry
2 answers:
Yanka [14]3 years ago
8 0

Answer:

Reaction c. has the largest value of \frac{k_{p} }{k_{c} } =  1.55 X 10^{10} at 300 K

Explanation:

Here is the complete question

Converting between Kc and Kp For which of the following reactions is the ratio Kp/Kc largest at 300 K?  

a. N2(g) + O2(g) ⇌ 2 NO(g)

b. C(s) +2H2(g) ⇌ CH4(g)

c. Ni(CO)4(g) ⇌ Ni(s) + 4CO(g)

d. CaCO3(s) ⇌ CaO(s) + CO2(g)

Solution

k_{p} = k_{c}(RT)^{n}\\\frac{k_{p} }{k_{c} } =  (RT)^{n}

where R = molar gas constant = 8.314 J/mol-K, T = temperature = 300 K and n = number of moles of products - number of moles of reactants

For reaction a. number of moles of gaseous products = 2, number of moles of gaseous reactants = 2. So n = 2 - 2 = 0

So, \frac{k_{p} }{k_{c} } =  (RT)^{n} = (RT)^{0} = 1

For reaction b. number of moles of gaseous products = 1, number of moles of gaseous reactants = 2. So n = 1 - 2 = -1 (we do not include the solid)

So, \frac{k_{p} }{k_{c} } =  (RT)^{n} = (RT)^{-1} = (8.314 X 300)^{-1} = (2494.2)^{-1} = 4.01   X 10^{-4}

For reaction c. number of moles of gaseous products = 5, number of moles of gaseous reactants = 1. So n = 4 - 1 = 3 (we do not include the solid)

So, \frac{k_{p} }{k_{c} } =  (RT)^{n} = (RT)^{3} = (8.314 X 300)^{3} = (2494.2)^{3} = 1.55 X 10^{10}

For reaction d. number of moles of gaseous products = 2, number of moles of gaseous reactants = 0. So n = 2 - 0 = 2 (we do not include the solid)

So, \frac{k_{p} }{k_{c} } =  (RT)^{n} = (RT)^{2} = (8.314 X 300)^{2} = (2494.2)^{2} = 6.22 X 10^{6}

Since \frac{k_{p} }{k_{c} } =  1.55 X 10^{10} for reaction c which is the largest value. So, reaction c. has the largest value of \frac{k_{p} }{k_{c} } =  1.55 X 10^{10} at 300 K

Novosadov [1.4K]3 years ago
3 0
Below are the choices:

<span>A. Ni(CO)4(g) ⇌ Ni(s) + 4CO(g)
B. C(s) +2H2(g) ⇌ CH4(g)
C. CaCO3(s) ⇌ CaO(s) + CO2(g)
D. N2(g) + O2(g) ⇌ 2 NO(g)
</span>
The answer is A. Ni(CO)4(g) ⇌ Ni(s) + 4CO(g)

<span>The Kp/Kc ratio is equal to (RT)Δn. K is a constant and the temperature is held constant. So, the Kp/Kc ratio depends on Δn or the difference of moles of gaseous product and reactant. The reaction with the greatest Kp/Kc ratio is Ni(CO)4(g) ⇌ Ni(s) + 4CO(g) with a Δn of 3.</span>
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                HB = \frac{2P}{\pi D [D - \sqrt{(D^{2} - d^{2})}]}    

Now, putting the given values into the above formula as follows.

                HB = \frac{2P}{\pi D [D - \sqrt{(D^{2} - d^{2})}]}                            = \frac{2 \times 1000 kg}{3.14 \times 10 mm [D - \sqrt{((10 mm)^{2} - (2.50)^{2})}]}  

                       = \frac{2000}{9.98}                          

                       = 200

Therefore, the Brinell HArdness is 200.

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               Brinell Hardness = 300

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                      d = \sqrt{(D^{2} - [D - \frac{2P}{HB} \pi D]^{2})}

                         = \sqrt{(10 mm)^{2} - [10 mm - \frac{2 \times 500 kg}{300 \times 3.14 \times 10 mm}]^{2}}

                          = 4.46 mm

Hence, the diameter of an indentation to yield a hardness of 300 HB when a 500-kg load is used is 4.46 mm.

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