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kumpel [21]
3 years ago
15

Two ice skaters approach each other at right angles. Skater A has a mass of 32.7 kg and travels in the x direction at 2.3 m/s. S

kater B has a mass of 93.3 kg and is moving in the y direction at 1.51 m/s. They collide and cling together. Find the final speed of the couple. Answer in units of m/s.
Physics
1 answer:
UkoKoshka [18]3 years ago
3 0

Answer:

Final speed, v = 1.25 m/s

Explanation:

Given that,

Mass of skater A, m_A=32.7\ kg

Initial speed of skater A, u_A=2.3i\ m/s (x axis)

Mass of skater B, m_B=93.3\ kg

Initial speed of skater B, u_B=1.51j\ m/s (y axis)

It is mentioned that the two skaters collide and cling together. It is case of inelastic collision in which momentum remains conserved. Let V is the final speed of the couple. It is given by :

m_Au_A+m_Bu_B=(m_A+m_B)V

32.7\times 2.3i+93.3\times 1.51j=(32.7+93.3)V

V=\dfrac{75.21i+140.88j}{126}

V=(0.59i+1.11j)\ m/s

|V|=1.25\ m/s

So, the final speed of the couple is 1.25 m/s. Hence, this is the required solution.

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