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kumpel [21]
3 years ago
15

Two ice skaters approach each other at right angles. Skater A has a mass of 32.7 kg and travels in the x direction at 2.3 m/s. S

kater B has a mass of 93.3 kg and is moving in the y direction at 1.51 m/s. They collide and cling together. Find the final speed of the couple. Answer in units of m/s.
Physics
1 answer:
UkoKoshka [18]3 years ago
3 0

Answer:

Final speed, v = 1.25 m/s

Explanation:

Given that,

Mass of skater A, m_A=32.7\ kg

Initial speed of skater A, u_A=2.3i\ m/s (x axis)

Mass of skater B, m_B=93.3\ kg

Initial speed of skater B, u_B=1.51j\ m/s (y axis)

It is mentioned that the two skaters collide and cling together. It is case of inelastic collision in which momentum remains conserved. Let V is the final speed of the couple. It is given by :

m_Au_A+m_Bu_B=(m_A+m_B)V

32.7\times 2.3i+93.3\times 1.51j=(32.7+93.3)V

V=\dfrac{75.21i+140.88j}{126}

V=(0.59i+1.11j)\ m/s

|V|=1.25\ m/s

So, the final speed of the couple is 1.25 m/s. Hence, this is the required solution.

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A charge of 32.0 nC is placed in a uniform electric field that is directed vertically upward and has a magnitude of 4.30x 104 V/
hodyreva [135]

A) The work done by the electric field is zero

B) The work done by the electric field is 9.1\cdot 10^{-4} J

C) The work done by the electric field is -2.4\cdot 10^{-3} J

Explanation:

A)

The electric field applies a force on the charged particle: the direction of the force is the same as that of the electric field (for a positive charge).

The work done by a force is given by the equation

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement of the particle

\theta is the angle between the direction of the force and the direction of the displacement

In this problem, we have:

  • The force is directed vertically upward (because the field is directed vertically upward)
  • The charge moves to the right, so its displacement is to the right

This means that force and displacement are perpendicular to each other, so

\theta=90^{\circ}

and cos 90^{\circ}=0: therefore, the work done on the charge by the electric field is zero.

B)

In this case, the charge move upward (same direction as the electric field), so

\theta=0^{\circ}

and

cos 0^{\circ}=1

Therefore, the work done by the electric force is

W=Fd

and we have:

F=qE is the magnitude of the electric force. Since

E=4.30\cdot 10^4 V/m is the magnitude of the electric field

q=32.0 nC = 32.0\cdot 10^{-9}C is the charge

The electric force is

F=(32.0\cdot 10^{-9})(4.30\cdot 10^4)=1.38\cdot 10^{-3} N

The displacement of the particle is

d = 0.660 m

Therefore, the work done is

W=Fd=(1.38\cdot 10^{-3})(0.660)=9.1\cdot 10^{-4} J

C)

In this case, the angle between the direction of the field (upward) and the displacement (45.0° downward from the horizontal) is

\theta=90^{\circ}+45^{\circ}=135^{\circ}

Moreover, we have:

F=1.38\cdot 10^{-3} N (electric force calculated in part b)

While the displacement of the charge is

d = 2.50 m

Therefore, we can now calculate the work done by the electric force:

W=Fdcos \theta = (1.38\cdot 10^{-3})(2.50)(cos 135.0^{\circ})=-2.4\cdot 10^{-3} J

And the work is negative because the electric force is opposite direction to the displacement of the charge.

Learn more about work and electric force:

brainly.com/question/6763771

brainly.com/question/6443626

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

5 0
3 years ago
Which of the following is a good scientific question? A. Are dragons lizards or birds? B. How do star fish fall in love? C. Does
Wittaler [7]
<span>C. Does eating less fat increase a mouse's lifespan?
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</span>This is a testable question that can be answered by designing and conducting an experiment.

I think D could be correct as well.

My final answer is D.


6 0
2 years ago
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KatRina [158]
The answer should be copper. hope this helps :D
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luda_lava [24]

Answer:

d

Explanation:

i think

5 0
2 years ago
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