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kumpel [21]
3 years ago
15

Two ice skaters approach each other at right angles. Skater A has a mass of 32.7 kg and travels in the x direction at 2.3 m/s. S

kater B has a mass of 93.3 kg and is moving in the y direction at 1.51 m/s. They collide and cling together. Find the final speed of the couple. Answer in units of m/s.
Physics
1 answer:
UkoKoshka [18]3 years ago
3 0

Answer:

Final speed, v = 1.25 m/s

Explanation:

Given that,

Mass of skater A, m_A=32.7\ kg

Initial speed of skater A, u_A=2.3i\ m/s (x axis)

Mass of skater B, m_B=93.3\ kg

Initial speed of skater B, u_B=1.51j\ m/s (y axis)

It is mentioned that the two skaters collide and cling together. It is case of inelastic collision in which momentum remains conserved. Let V is the final speed of the couple. It is given by :

m_Au_A+m_Bu_B=(m_A+m_B)V

32.7\times 2.3i+93.3\times 1.51j=(32.7+93.3)V

V=\dfrac{75.21i+140.88j}{126}

V=(0.59i+1.11j)\ m/s

|V|=1.25\ m/s

So, the final speed of the couple is 1.25 m/s. Hence, this is the required solution.

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. A mass m is traveling at an initial speed of 25.0 m/s. It is brought to rest in a distance of 62.5 m by a net force of 15.0 N.
harkovskaia [24]

Answer:

m = 3 kg

The mass m is 3 kg

Explanation:

From the equations of motion;

s = 0.5(u+v)t

Making t thr subject of formula;

t = 2s/(u+v)

t = time taken

s = distance travelled during deceleration = 62.5 m

u = initial speed = 25 m/s

v = final velocity = 0

Substituting the given values;

t = (2×62.5)/(25+0)

t = 5

Since, t = 5 the acceleration during this period is;

acceleration a = ∆v/t = (v-u)/t

a = (25)/5

a = 5 m/s^2

Force F = mass × acceleration

F = ma

Making m the subject of formula;

m = F/a

net force F = 15.0N

Substituting the values

m = 15/5

m = 3 kg

The mass m is 3 kg

7 0
3 years ago
A box sits at rest on a rough 33° inclined plane. Draw the free-body diagram, showing all the forces
Cloud [144]

(a) The free body of all the forces include, frictional force, weight of the box acting perpendicular and another acting parallel to the plane.

(b) When the box is sliding down, the frictional force acts towards the right.

(c) When the box slides up, the direction of the frictional force changes, it acts towards the left.

<h3>Free body diagram</h3>

The free body diagram of all the forces on the box is obtained by noting the upward force and downward forces on the box as shown below;

                      /  W2

                    Ф → Ff

                    ↓W1

where;

  • Ff is the frictional force resisting the down motion of the box
  • W1 is the perpendicular component of the box weight = Wcos(33)
  • W2 is the parallel component of the box weight = Wsin(33)

(b) When the box is sliding down, the frictional force acts towards the right.

(c) When the box slides up, the direction of the frictional force changes, it acts towards the left.

Learn more about free body diagram of inclined objects here: brainly.com/question/4176810

8 0
2 years ago
What would the answer be ?
Marianna [84]
The second one since you’re changing the soil up by adding different fertilisers. This will be you’re independent variable. And you’re dependent variable is your result = the plant height .
Hope this helps :)
4 0
3 years ago
Paula has walked in a straight line, 30.5° north of west, for 1650 meters. How far south and east should she walks to return to
olchik [2.2K]
The answer is A.
Sy = 1650 x sin30.5 = 837.4 m toward south
Sx = 1650 x cos30.5 = 1421.7 m toward east
8 0
3 years ago
Describe the valence electrons in nitrogen and how it could bond to other atoms?
Gekata [30.6K]

Answer:

Each nitrogen molecule consists of two atoms of nitrogen that are bonded by a triple covalent bond. This is because each nitrogen atom has 5 valence electrons. Each atom can complete its octet by sharing three electrons.

I hope this helps!

4 0
3 years ago
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