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aleksandrvk [35]
4 years ago
12

How to express whole numbers in scientific notation?

Physics
1 answer:
SCORPION-xisa [38]4 years ago
5 0

Answer:

To write a number in scientific notation. First write a decimal point in the numbers so that there's only one digit to the left of the decimal point.

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A large spool in an electrician's workshop has 55 m of insulation coated wire coiled around it. when the electrician connects a
goblinko [34]

Answer:

21.2 m

Explanation:

The current in the wire is given by Ohm's law:

I=\frac{V}{R}

where V is the voltage of the battery and R is the resistance of the wire.

The resistance of the wire is directly proportional to the length of the wire, so we can write:

R=kL

where k is a constant and L is the length of the wire. Substituting into the first equation,

I=\frac{V}{kL}

We can rewrite this equation also as

\frac{V}{k}=IL

where the term on the left is a constant (because the voltage of the battery does not change). So, we can write:

I_1 L_1 = I_2 L_2

where:

I_1 = 1.0 A is the current in the first situation

L_1 = 55 m is the length of the wire in the first situation

I_2 = 2.6 A is the current in the second situation

L_2=? is the length of the wire in the second situation

Re-arranging the formula, we can find the value of L2:

L_2 = \frac{I_1 L_1}{I_2}=\frac{(1.0 A)(55 m)}{2.6 m}=21.2m

8 0
3 years ago
You are at a train station, standing next to the train at the front of the first car. The train starts moving with constant acce
yarga [219]

Answer:

The answer is t = 23.81 s

Explanation:

A car in this question means those partition that make up the train

       Let denote the the of each car as Z

 The equation of motion that has to do with distance is given as

                 S = ut + (1/2)at²

          Where u = initial velocity = 0

                       t = time = 9 s

 Substituting these values we have

                       Z = (1/2) a(9)²

                          = 40.5 a

making acceleration the subject we have that a = Z / 40.5

                    Let us denote the length of the 7th car as  =7Z

Considering the distance at the 7th car we have

                    S₇ = ut₇ + (1/2)at²₇

          Where  u = initial velocity =0

     Substituting values we have

                    7Z = (1/2)(Z/40.5)(t₇)²

                      7  = {1/2 ×40.5}(t₇)²

                    t₇²  = 7 × 2 × 40.5

                   t₇²    =  567

                   t₇     =  23.81 s

                   

             

8 0
3 years ago
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