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atroni [7]
3 years ago
10

Nuclear chemistry findings contradict __________________ theory of indivisible atoms.

Chemistry
1 answer:
Novosadov [1.4K]3 years ago
3 0

Answer:

atomic theory

Explanation:

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How do you explain reaction of stiochiometry
Mama L [17]

Answer:

Chemical reactions are balanced by adding coefficients so that the number of atoms of each element is the same on both sides. Stoichiometry describes the relationship between the amounts of reactants and products in a reaction.

Explanation:

3 0
3 years ago
A sample of water vapor has a volume of 3.15 L, a pressure of 2.40 atm, and a temperature of 325 K. What is the new temperature,
lara31 [8.8K]

Answer:

The answer to your question is:   T2 = 235.44 °K

Explanation:

Data

V1 = 3.15 L                    V2 = 2.78 L

P1 = 2.40 atm               P2 = 1.97 atm

T1 = 325°K                    T2 = ?

Formula

\frac{P1V1}{T1} = \frac{P2V2}{T2}

Process

            T2 = (P2V2T1) / (P1V1)

            T2 = (1.97x 2.78x 325) / (2.40 x 3.15)

            T2 = 1779.895 / 7.56

            T2 = 235.44 °K

4 0
3 years ago
Which element could not form in the sun and would have to be formed in a supernova?.
sasho [114]
Uranium, most uranium does derive from a star. However, not from our sun.
7 0
2 years ago
Calculate the volume of hydrogen if you have 12.1 moles of Hydrogen.
vodomira [7]

To Find :

The volume of 12.1 moles hydrogen at STP.

Solution :

We know at STP, 1 mole of gas any gas occupy a volume of 22.4 L.

Let, volume of 12.1 moles of hydrogen is x.

So, x = 22.4 × 12.1 L

x = 271.04 L

Therefore, the volume of hydrogen gas at STP is 271.04 L.

8 0
2 years ago
Limestone (CaCO3) is decomposed by heating to quicklime (CaO) and carbon dioxide. Calculate how many grams of quicklime can be p
Harman [31]

Answer: 2800 g

Explanation:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass = 5 kg = 5000 g

\text{Number of moles}=\frac{5000g}{100g/mol}=50moles

1 mole of CaCO_3 produces = 1 mole of CaO

50 moles of CaCO_3 produces =\frac{1}{1}\times 50=50moles of CaO

Mass of CaO=moles\times {\text{Molar mass}}=50moles\times 56g/mole=2800g

2800 g of CaO is produced from 5.0 kg of limestone.

3 0
3 years ago
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