Question

A squirrel drops an acorn from a tree branch that is 8.0 m from the ground. How long is the acorn in the air?What is the acorn's velocity when it reaches the ground?

Answer 1

Answer:

time = 1.277 second

velocity = 12.52 m/s

Explanation:

Given data

height = 8 m

top find out

How long is the acorn and  acorn's velocity

solution

we know that initial velocity is zero

and acceleration due to gravity is roughly 9.81 m/s2

so equation for time t  will be

time = √(2h/g)

time = √(2(8)/9.81)

time = 1.277 second

and

velocity will be

velocity = √(2gh)

velocity = √(2(9.81)8)

velocity = 12.52 m/s

Answer 2

Answer:

Part a)

$t = 1.28 s$

Part b)

$v_f = 12.53 m/s$

Explanation:

Part a)

As we know that motion of squirrel in air is uniformly accelerated motion

So we have

$y = \frac{1}{2}gt^2$

we have

$y = 8.0 m$

$8 = \frac{1}{2}(9.81)t^2$

$t = 1.28 s$

Part b)

For finding velocity we can use kinematics

$v_f = v_i + at$

$v_f = 0 + (9.81)(1.28)$

$v_f = 12.53 m/s$