Here, height is given which will be the distance for a freely falling object.
The velocity will be
and the acceleration will be
In this way, the formula works.
The third (left hand corner) since the x and y are both negative.
The same cycle of phases repeats over and over and over and over and over again, so I could start the list with whatever phase I want, and build the list until I get to the same phase I started with.
But the cultures that track their months by the phases of the Moon (traditional Muslim, traditional Jewish, traditional Chinese) all start the new month with the New Moon, so I guess I'll start my list there too.
-- New Moon
-- Waxing Crescent
-- First Quarter
-- Waxing Gibbous
-- Full Moon
-- Waning Gibbous
-- Third Quarter
-- Waning Crescent
-- next New Moon
Assume the acceleration due to gravity is approximately 9.8 m/s^2
In 1 second, it will fall
s = ut + at^2/2
u = initial vertical velocity = 0
a = 9.8
t = 1
s is the distance it falls
= 9.8/2 = 4.9 m
But the parcel has a horizontal velocity of 1 m/s so it will travel 1 m horizontally in 1 second.
The answer would be
1 metre, 4.9 metres.
