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Margarita [4]
3 years ago
13

Why is it NOT possible for ONE particle (atom/ion/molecule) to be classified as a particular phase, or state, of matter?

Chemistry
1 answer:
Agata [3.3K]3 years ago
6 0

Answer:

because I said and I'm the boss

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Karolina [17]
To be honest I don’t even know
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3 years ago
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What geological process(es) could form magnesium silicate perovskite at 500 C?
dimulka [17.4K]

Magnesium silicate is a compound of magnesium oxide and silicon. It is the magnesium salt of silicic acid containing an unspecified amount of water. The molecular formula can be expressed more clearly as MgSiO3.

7 0
2 years ago
What is the name of the ability to use up energy in one second
Savatey [412]

Answer:

Work

Explanation:

Work is defined as the ability to use energy in one second and its SI unit is same as energy that is joule.

Work refers to the energy utilized to displace an object over a distance by an external force in one direction and in given time period which can be one second as well.

Hence, the correct answer is "work".

5 0
3 years ago
34. 3.15 mol of an unknown solid is placed into enough water to make 150.0 mL of solution. The solution's temperature increases
Digiron [165]

Answer:

ΔH = 2.68kJ/mol

Explanation:

The ΔH of dissolution of a reaction is defined as the heat produced per mole of reaction. We have 3.15 moles of the solid, to find the heat produced we need to use the equation:

q = m*S*ΔT

<em>Where q is heat of reaction in J,</em>

<em>m is the mass of the solution in g,</em>

<em>S is specific heat of the solution = 4.184J/g°C</em>

<em>ΔT is change in temperature = 11.21°C</em>

The mass of the solution is obtained from the volume and the density as follows:

150.0mL * (1.20g/mL) = 180.0g

Replacing:

q = 180.0g*4.184J/g°C*11.21°C

q = 8442J

q = 8.44kJ when 3.15 moles of the solid react.

The ΔH of the reaction is:

8.44kJ/3.15 mol

= 2.68kJ/mol

5 0
3 years ago
GoOd MoRnInG <br> EvErY OnE <br> BlA BlA BlA BlA
azamat

Answer:

you too ^^

Explanation:

4 0
3 years ago
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