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AfilCa [17]
3 years ago
13

A neutron in a nuclear reactor makes an elastic head-on collision with a carbon atom initially at rest. (The mass of the carbon

atom is 12 times that of the neutron.) What fraction of the neutron's kinetic energy is transferred to the carbon atom?

Physics
1 answer:
Alecsey [184]3 years ago
7 0

Answer:

The fraction of the neutron's kinetic energy is 0.284.

Explanation:

explanation is in the following attachment        

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These four surfaces are opaque; that is they reflect or absorb certain rays of light determine the color
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Similarly, in the  second figure, the surface absorbs all colors except for blue, and so the surface will appear blue to our eyes.

In the third figure, the surface absorbs all colors, so it will appear black to our eyes (because no colors are reflected, and black=absence of colors).

In the fourth figure, all colors are reflected: this means the surface will appear white to our eyes (white= sum of all colors).
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The speed of an object and direction of its travel is?
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If an object is accelerating, it is traveling the same distance for each time interval of its motion
Anika [276]

Answer:

false

Explanation:

if an object is accelerating the object will not travel the same distance every time interval

4 0
3 years ago
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3. A 142 g baseball is thrown at a speed of 42.9 m/s. What is the kinetic energy of the baseball at this moment?
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8 0
3 years ago
How do your results from ray tracing compare to your results from using the thin-lens equation?
EastWind [94]

Answer:

20cm

Explanation:

A convex lens has a positive focal length and the object placed in front of it produce both virtual and real image <em>(image distance can be negative or positive depending on the nature of the image</em>).

According to the lens equation

\frac{1}{f} = \frac{1}{u} + \frac{1}{v} where;

f is the focal length  of the lens

u is the object distance

v is the image distance

If the magnification is - 0.6

mag = v/u = -0.5

v = -0.5u

since v = 10cm

10 = -0.5u

u = -10/0.5

u =-20 cm

Substitute u = -20cm ( due to negative magnification)and v = 10cm into the lens formula to get the focal length f

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}\\\frac{1}{f} = \frac{1}{-20} + \frac{1}{10}\\\frac{1}{f} = \frac{1}{-20} + \frac{1}{10}\\\frac{1}{f} = \frac{-1+2}{20} \\\frac{1}{f} = \frac{1}{20} \\cross \ multiply\\f = 20\\f = 20 cm

Hence the focal length of the convex lens is 20cm

7 0
3 years ago
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