The isotope U-235 is important because under certain conditions it can readily be split, yielding a lot of energy. It is therefore said to be 'fissile' and we use the expression 'nuclear fission'. Meanwhile, like all radioactive isotopes, they decay.
Balanced chemical reaction: Pb(NO₃)₂ (aq) + 2NaI(aq) → 2PbI₂(s) + 2NaNO₃(aq).
V(Pb(NO₃)₂) = 50 mL ÷ 1000 mL = 0.05 L, volume of solution.
c(Pb(NO₃)₂) = 0.1 mol/L; concentration of solution.
n(Pb(NO₃)₂) = c(Pb(NO₃)₂) · V(Pb(NO₃)₂).
n(Pb(NO₃)₂) = 0.1 mol/L · 0.05 L.
n(Pb(NO₃)₂) = 0.005 mol.
n(NaI) = c(NaI) · V(NaI).
n(NaI) = 0.1 mol/L · 0.05 L.
n(NaI) = 0.005 mol; amount of substance.
From chemical reaction: n(Pb(NO₃)₂) : n(NaI) = 1 : 2.
n(Pb(NO₃)₂) = 0.005 mol ÷ 2.
n(Pb(NO₃)₂) = 0.0025 mol; number of moles Pb(NO₃)₂ used.
n(NaI) = 0.005 mol; number of moles NaI used.
The limiting reagent is Pb(NO₃)₂.
n(PbI₂) = 0.005 mol.
m(PbI₂) = n(PbI₂) · M(PbI₂).
m(PbI₂) = 0.005 mol · 461 g/mol.
m(PbI₂) = 2.305 g; the theoretical yield of PbI₂.
Answer:
Part A = The mass of sulfur is 6.228 grams
Part B = The mass of 1 silver atom is 1.79 * 10^-22 grams
Explanation:
Part A
Step 1: Data given
A mixture of carbon and sulfur has a mass of 9.0 g
Mass of the product = 27.1 grams
X = mass carbon
Y = mass sulfur
x + y = 9.0 grams
x = 9.0 - y
x(molar mass CO2/atomic mass C) + y(molar mass SO2/atomic mass S) = 22.6
(9 - y)*(44.01/12.01) + y(64.07/32.07)
(9-y)(3.664) + y(1.998)
32.976 - 3.664y + 1.998y = 22.6
-1.666y = -10.376
y = 6.228 = mass sulfur
x = 9.0 - 6.228 = 2.772 grams = mass C
The mass of sulfur is 6.228 grams
Part B
Calculate the mass, in grams, of a single silver atom (mAg = 107.87 amu ).
Calculate moles of 1 silver atom
Moles = 1/ 6.022*10^23
Moles = 1.66*10^-24 moles
Mass = moles * molar mass
Mass = 1.66*10 ^-24 moles *107.87
Mass = 1.79 * 10^-22 grams
The mass of 1 silver atom is 1.79 * 10^-22 grams
Answer:
-32 Fahrenheit converts to 237.594 Kelvin
Glucose molecule has 6 carbon atoms
