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3 years ago

In the reaction 2CO (g) + O2 (g) 2CO2 (g), how many moles of oxygen gas are needed to react with 24 moles of carbon monoxide

Chemistry

1 answer:

Anuta_ua [19.1K]3 years ago

4 0

12 moles of oxygen gas are needed to react with 24 moles of carbon monoxide.

<u>Explanation:</u>

The molar ratio of carbon monoxide to oxygen 2:1

Which means 2 moles of carbon monoxide is reacting with 1 mole of oxygen.

to produce 2 moles of carbon dioxide.

Therefore, from the molar ratio, we get that 12 moles of oxygen are required to react with 24 moles 0f carbon monoxide.

Molar ratio:

The molar ratio gives the moles of product that are formed from a certain amount of reactant, and also the number of moles of a reactant needed to react with another reactant.

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Radioactive decay can be described by the following equation where is the original amount of the substance, is the amount of the

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Answer:

Iron remains = 17.49 mg

Explanation:

Half life of iron -55 = 2.737 years (Source)

$t_{1/2}=\frac {ln\ 2}{k}$

Where, k is rate constant

So,

$k=\frac {ln\ 2}{t_{1/2}}$

$k=\frac {ln\ 2}{2.737}\ year^{-1}$

The rate constant, k = 0.2533 year⁻¹

Time = 2.41 years

$[A_0]$ = 32.2 mg

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

So,

$[A_t]=32.2\times e^{-0.2533\times 2.41}\ mg$

$[A_t]=32.2\times e^{-0.610453}\ mg$

$[A_t]=17.49\ mg$

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3 years ago

You can decide if a paint booth filter is hazardous waste by answering which of the following questions:

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Answer: (D) Are there solvents mixed in (or is it water based)?

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3 years ago

The freezing point of a nonelectrolyte solution containing 30.0 g of a solute dissolved in 250.0 g of water is observed to be -2

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Answer:

Molar mass of solute is 89.28 g/m

Explanation:

Colligative property of freezing point depression to solve this:

ΔT = Kf . m . i

i = number of particles, dissolved in solution. In this case, it is a nonelectrolyte, so i = 1.

m = molalilty (mol of solute/1kg of solvent

ΔT = T° freeze pure solvent - T° freeze solution

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2.50°C / 1.86 m/°C = m

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This means, that in 1000 g of solvent, we have 1.34 moles but we have 250 g of solvent, so let's make a rule of three.

1000 g ____ 1.34 moles

250 g _____(2.50 . 1.34) / 1000 = 0.336 moles

To find the molar mass, we divide mass / moles

30 g/ 0.336 moles = 89.28 g/m

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3 years ago

What is a cone of depression

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