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Evgen [1.6K]
3 years ago
9

In the reaction 2CO (g) + O2 (g) 2CO2 (g), how many moles of oxygen gas are needed to react with 24 moles of carbon monoxide

Chemistry
1 answer:
Anuta_ua [19.1K]3 years ago
4 0

12 moles of oxygen gas are needed to react with 24 moles of carbon monoxide.

<u>Explanation:</u>

The molar ratio of carbon monoxide to oxygen 2:1

Which means 2 moles of carbon monoxide is reacting with 1 mole of oxygen.

to produce 2 moles of carbon dioxide.

Therefore, from the molar ratio, we get that 12 moles of oxygen are required to react with 24 moles 0f carbon monoxide.

Molar ratio:

The molar ratio gives the moles of product that are formed from a certain amount of reactant, and also the number of moles of a reactant needed to react with another reactant.

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The density of human blood is 1.06g/ml the volume is 5.5l what is the mass in kg
kondor19780726 [428]

The mass of the blood is 5.8 kg.

<em>V</em> = 5.5 L = 5500 mL

Mass = 5500 mL × (1.06 g/1 mL) = 5800 g = 5.8 kg

6 0
3 years ago
4/5(2x 5)−4=1
uysha [10]
 5/8=0.625 4/5=.8


5/8 because 5/8=0.625 and because its 2x you multiply 0.625 by 2=1.25 then you do 1.25+5=6.25 4/5=.8    6.25 times .8=5 5-4=1   


X=5/8 or 0.625

5 0
3 years ago
A particle accelerates from rest with an acceleration of 8.0m/s2. Calculate its velocity after 150s. What kinematic formula must
Ipatiy [6.2K]

<u>Answer</u>:

Final velocity: 1200 m/s

<u>Explanation</u>:

Formula:   \overline{a} = \frac{v - v_0}{t} = \frac{\Delta v}{\Delta t}

<u>Where</u>:

a = average acceleration

v = final velocity

vo = starting velocity

t = elapsed time

<em>Here the final velocity is unknown which we have to find. The initial is 0 m/s</em>

<em>as it was at rest. The time taken: 150 seconds. Acceleration given 8.0 m/s²</em>

using the formula:

\overline{a} = \frac{v - v_0}{t}

8 = \frac{v - 0}{150}

v = 1200 m/s

4 0
2 years ago
Read 2 more answers
Economics is about the production of goods and services which requires that allocation of what
yuradex [85]

It requires the allocation of resources.

6 0
3 years ago
Copper (II) sulfate pentahydrate may be heated to drive off the water of hydration. If 5 g of water are produced, what was the o
____ [38]

Answer:

13.9g of CuSO4•5H2O

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CuSO4•5H2O → CuSO4 + 5H2O

Next, we shall determine the mass of CuSO4•5H2O heated and the mass of H2O produced from the balanced equation.

This is illustrated below

Molar mass of CuSO4• 5H2O = 63.5 + 32 + (16x4) + 5(2x1 + 16)

= 63.5 + 32 + 64 + 5(18) = 249.5g/mol

Mass of CuSO4•5H2O from the balanced equation = 1 x 249.5 = 249.5g

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mass of H2O from the balanced equation = 5 x 18 = 90g

From the balanced equation above,

249.5g of CuSO4•5H2O produced 90g of H2O.

Now, we can determine the mass of CuSO4•5H2O needed to produce 5g of H2O. This can be achieved as shown below:

From the balanced equation above,

249.5g of CuSO4•5H2O produced 90g of H2O.

Therefore, Xg of CuSO4•5H2O will produce 5g of H2O i.e

Xg of CuSO4•5H2O = (249.5 x 5)/90

Xg of CuSO4•5H2O = 13.9g

Therefore, 13.9g of CuSO4•5H2O is needed to produce 5g of H2O.

6 0
3 years ago
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